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I'm trying to find a way to find the length of an integer (number of digits) and then place it in an integer array. The assignment also calls for doing this without the use of classes from the STL, although the program spec does say we can use "common C libraries" (gonna ask my professor if I can use cmath, because I'm assuming log10(num) + 1 is the easiest way, but I was wondering if there was another way).
Ah, and this doesn't have to handle negative numbers. Solely non-negative numbers.
I'm attempting to create a variant "MyInt" class that can handle a wider range of values using a dynamic array. Any tips would be appreciated! Thanks!
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int num; scanf("%d",&num); char testing[100]; sprintf(testing,"%d",num); int length = strlen(testing); Alternatively, you can do this mathematically using the log10 function.
Perhaps the easiest way of getting the number of digits in an Integer is by converting it to String, and calling the length() method. This will return the length of the String representation of our number: int length = String. valueOf(number).
The length of an integer field is defined in terms of number of digits; it can be 3, 5, 10, or 20 digits long. A 3-digit field takes up 1 byte of storage; a 5-digit field takes up 2 bytes of storage; a 10-digit field takes up 4 bytes; a 20-digit field takes up 8 bytes.
The number of digits of an integer n in any base is trivially obtained by dividing until you're done:
unsigned int number_of_digits = 0; do { ++number_of_digits; n /= base; } while (n); If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
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