C++ get each digit in int

Question

I have an integer:

int iNums = 12476;

And now I want to get each digit from iNums as integer. Something like:

foreach(iNum in iNums){
   printf("%i-", iNum);
}

So the output would be: "1-2-4-7-6-". But i actually need each digit as int not as char.

Thanks for help.

Answer 1

void print_each_digit(int x)
{
    if(x >= 10)
       print_each_digit(x / 10);

    int digit = x % 10;

    std::cout << digit << '\n';
}