Special simple random number generator

Question

How to create a function, which on every call generates a random integer number? This number must be most random as possible (according to uniform distribution). It is only allowed to use one static variable and at most 3 elementary steps, where each step consists of only one basic arithmetic operation of arity 1 or 2.

Example:

int myrandom(void){
  static int x;
  x = some_step1;
  x = some_step2;
  x = some_step3;
  return x;
}

Basic arithmetic operations are +,-,%,and, not, xor, or, left shift, right shift, multiplication and division. Of course, no rand(), random() or similar stuff is allowed.

Answer 1

Linear congruential generators are one of the oldest and simplest methods:

int seed = 123456789;

int rand()
{
  seed = (a * seed + c) % m;
  return seed;
}

Only a few instruction with basic arithmetic operations, that's all you need.

Mind that this algorithm works fine only if a, c and m are chosen in a particular way!

To guarantee the longest possible period of this sequence, c and m should be coprime, a − 1 should be divisible by all prime factors of m, and also for 4 if m is divisible by 4.

Some examples of parameters are shown on Wikipedia: for example ANSI C for some compilers proposes m = 2 ³¹, a = 1103515245 and c = 12345.

Answer 2

public long randomLong() {
  x ^= (x << 21);
  x ^= (x >>> 35);
  x ^= (x << 4);
  return x;
}

Seed cannot be 0. Source: http://www.javamex.com/tutorials/random_numbers/xorshift.shtml#.VlcaYzKwEV8

Additional info in wiki: https://en.wikipedia.org/wiki/Xorshift