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C++ - Function with multiple parameter packs and a std::function as argument

I am trying to create an IoC Container in C++ that resolves dependencies automatically.

For that I created a function with two variadic parameter packs that is declared like this:

template <class T, typename ... TDependencies, typename... TArgs> 
void Register(std::function<std::shared_ptr<T> (std::shared_ptr<TDependencies> ...,
TArgs ...)> && pFactory)

Apparently, it seems the compiler is unable to match this when supplied with

Register<Foo, Bar>(std::function<std::shared_ptr<Foo>(std::shared_ptr<Bar>)>(
[](std::shared_ptr<Bar> bar){return std::make_shared<Foo>(bar);}));

The compile errors say

note: candidate: 'void Container::Register(std::function<std::shared_ptr<_Tp>
(std::shared_ptr<TDependencies>..., TArgs ...)>&&)
[with T = Foo; TDependencies = {Bar}; TArgs = {std::shared_ptr<Bar>}]'

Apparently, it matches std::shared_ptr<Bar> twice. How can I get the compiler not to match the shared_ptr in TArgs too?

like image 607
climb4 Avatar asked Sep 04 '21 21:09

climb4


1 Answers

Rather than trying to deduce TDependencies directly from the pFactory parameter type, I'd write a type trait to get the dependencies from the whole parameter pack instead. With boost::mp11:

template <class>
struct is_shared_ptr : std::false_type {};

template <class T>
struct is_shared_ptr<std::shared_ptr<T>> : std::true_type {};

namespace mp11 = ::boost::mp11;

template <class... Ts>
using register_traits = mp11::mp_partition<mp11::mp_list<Ts...>, is_shared_ptr>;

template <class T, class F, class... TDependencies, class... TArgs>
void RegisterImpl(F && pFactory,
                  mp11::mp_list<
                      mp11::mp_list<std::shared_ptr<TDependencies>...>,
                      mp11::mp_list<TArgs...>>);

template <class T, class... Ts> 
void Register(std::function<std::shared_ptr<T> (Ts...)> && pFactory)
{
    return RegisterImpl<T>(
        std::forward<std::function<std::shared_ptr<T> (Ts...)>>(pFactory),
        register_traits<Ts...>{});
}

And to call it:

Register(std::function{[] (std::shared_ptr<Bar> bar) {
    return std::make_shared<Foo>(bar);
}});

Try it on godbolt.org.

If boost::mp11 is not an option, here's how you can implement your own partition template metafunction:

template <class...>
struct list {};

namespace detail {
template <class L, template <class...> class P, class T, class F, class = void>
struct partition;

template <class Next, class... Ls,
          template <class...> class P, class T, class... Fs>
struct partition<list<Next, Ls...>, P, T, list<Fs...>,
                 std::enable_if_t<!P<Next>::value>> :
       partition<list<Ls...>, P, T, list<Fs..., Next>> {};

template <class Next, class... Ls,
          template <class...> class P, class... Ts, class F>
struct partition<list<Next, Ls...>, P, list<Ts...>, F,
                 std::enable_if_t<P<Next>::value>> :
       partition<list<Ls...>, P, list<Ts..., Next>, F> {};

template <template <class...> class P, class T, class F>
struct partition<list<>, P, T, F> { using type = list<T, F>; };
} // namespace detail

template <class L, template <class...> class P>
using partition = typename detail::partition<L, P, list<>, list<>>::type;

template <class... Ts>
using register_traits = partition<list<Ts...>, is_shared_ptr>;

template <class T, class F, class... TDependencies, class... TArgs>
void RegisterImpl(F && pFactory,
                  list<list<std::shared_ptr<TDependencies>...>, list<TArgs...>>);

Try it on godbolt.org.

The rest of the code will remain the same.

like image 120
Patrick Roberts Avatar answered Oct 23 '22 20:10

Patrick Roberts