I have two C functions f1
and f2
that take the same arguments. Based on a condition, I need to invoke one or the other one with the same arguments:
if (condition) {
result = f1(a, b, c);
} else {
result = f2(a, b, c);
}
I understand it is possible to use the syntax:
result = condition ? f1(a, b, c) : f2(a, b, c)
Is it be possible to have a DRY syntax that requires to write arguments a single time?
Yes, it works fine just like you suggested.
The function call operator ()
just needs a left-hand-side that evaluates to a function pointer, which names of functions do.
There's no need to derefence function pointers when calling, the ()
operator does that.
This sample program demonstrates:
#include <stdio.h>
static int foo(int x) {
return x + 1;
}
static int bar(int x) {
return x - 1;
}
int main(void) {
for (int i = 0; i < 10; ++i)
printf("%d -> %d\n", i, (i & 1 ? foo : bar)(i));
return 0;
}
It prints:
0 -> -1
1 -> 2
2 -> 1
3 -> 4
4 -> 3
5 -> 6
6 -> 5
7 -> 8
8 -> 7
9 -> 10
There is nothing strange here.
And since C predates Python by a fair bit, perhaps it's Python's semantics that are C-ish here. Or just plain sane, of course. :)
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