Assume I have a template class TemplateClass
with a template function templFcn
as follows:
template <typename T>
struct TemplateClass {
template <bool Bool> void templFcn(int i) { }
};
void test() {
TemplateClass<float> v;
v.templFcn<true>(0); // Compiles ok.
}
Now I would like to write a forward
function to emulate this behavior
template <typename T, template<typename> class C, bool Bool>
void forward(C<T>& v) {
v.templFcn<Bool>(0); // Compiler error, Line 16 (see below)
};
void test2() {
TemplateClass<float> v;
forward<float,TemplateClass,true>(v); // Line 21
}
Compiler error by clang++:
test.cc:16:5: error: reference to non-static member function must be called
v.templFcn<Bool>(0);
~~^~~~~~~~
test.cc:21:3: note: in instantiation of function template specialization
'forward<float, TemplateClass, true>' requested here
forward<float,TemplateClass,true>(v);
^
test.cc:3:29: note: possible target for call
template <bool Bool> void templFcn(int i) { }
^
1 error generated.
Can someone explain why such template forward failed in this case? And is there any way to circumvent it? Thanks!
v.template templFcn<Bool>(0); // Compiler error, Line 16 (see below)
Dependent clauses need disambiguation, so it knows <
is a template clause opener, not less-than.
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