C fgets() how to tell if line is greater than specified size

Question

I am using fgets() to read lines from popen("ps -ev", "r") and I cannot find out how to know if fgets() reads a line partially or fully, and if partially how to read/throw away the excess.

When reading each line from popen(), I am reading in the first 1024 characters and getting the information I need from that, which works perfectly fine. The issue arises when the lines are greater than 1024 characters and then the next line I read is a continuation of the previous line, which is not in the format I need (that being the value of each column at the beginning of each line). If I can know if I only partially read a line (that being the line has 1024 or more characters, I want to read and throw away every 1024 characters until it reaches the end. Once at the end, I can call fgets() again and this time it will read from the beginning of the next line rather than the continuation of the previous line.

I know that fgets() reads up until it either finds a newline or until it reaches the provided limit, and then continues reading the remaining part of the line. I have tried checking that the last character is '\0' and that the second last character in the line is '\n', but that does not work. I will post that code below in case that helps.

If you run the code, you will see LINE: num S num:num.num ... (where num is a number) which is what each line should begin with. Some lines will instead look something like LINE: AAAAAAQAAABMAAAAQAAAAAAAAAAMAAAAFAAAAEAAAAAAAAAADAAAACwAAABA.... These are the lines that are excess from the previous line, and these are the ones causing the issues since they are not in the correct format.

Any and all help is highly appreciated.

#include <stdlib.h>
#include <stdio.h>
#include <string.h>
#include <math.h>

#define NEWLINE() printf("\n");
#define DIVIDER() printf("============================================================================\n");
#define PL(l) printf("LINE: %s\n", l);

int const MAX_PROCESSES = 20;
int const BUFFER_SIZE = 1024;

int exhaustedLine(char* line) {
    if (line[sizeof line - 1] == '\0' && line[sizeof line - 2] != '\n') {
        printf("n:%c 0:%c\n", line[sizeof line - 2], line[sizeof line - 1]);
        NEWLINE();
        return -1;
    }
    return 0;   
}

int main(int argc, char const *argv[]) {
    FILE* fp = popen("ps -ev", "r");
    char buf[BUFFER_SIZE];
    char* line = (char*)1;

    while (line) {
        DIVIDER();
        line = fgets(buf, BUFFER_SIZE, fp);
        PL(line);
        if (exhaustedLine(line) != 0) {
            printf("END OF LINE\n");
        }
    }

    return 0;
}

Answer 1

You have the right idea: If a complete line was read, the buffer contains a newline. Otherwise the line is either longer than the buffer size or we are at the end of the file and the last line was unterminated.

The main problem with your implementation is char* line ... sizeof line. sizeof yields the size of the type of its operand expression, so sizeof line means sizeof (char *), which is the size of a pointer, not the size of the array line is pointing into.

Also, if a shorter line was read, then line[SIZE - 1] would access uninitialized memory.

Easiest solution:

int is_full_line(const char *line) {
    return strchr(line, '\n') != NULL;
}

Just use strchr to search the string for '\n'.

To throw away the rest of an overlong line, you have several options:

• You could call fgets again in a loop.
• You could call fgetc in a loop: int c; while ((c = fgetc(fp)) != EOF && c != '\n') {}
• You could use fscanf: fscanf(fp, "%*[^\n]"); fscanf(fp, "%*1[\n]");

---

Regarding

int const BUFFER_SIZE = 1024;

Note that const does not declare constants in C; it declares read-only variables. char buf[BUFFER_SIZE] is considered a variable-length array because the size is not a constant.

To get a true integer constant in C, you need to use enum instead:

enum { BUFFER_SIZE = 1024 };