C++ extend inherited functions

Question

considering a simple inherited class:

class Base 
{
  void func() {
     cout << "base" << endl;
  }
};

class Derived : public Base
{
  void func() {
      cout << "derived" << endl;
  } 
};

if I run Derived::func() I get

derived

I would like to modify this code to get

base
derived

Something more similar to an extension than an overriding.

I've been able to get something similar with constructors, but not with normal functions.

Many thanks, Lucio

Answer 1

class Derived : public Base
{
  void func() {
      Base::func();   // Call the base method before doing our own.
      cout << "derived" << endl;
  } 
};

Answer 2

To access the base-class function from the derived class, you can simply use:

Base::func();

In your case, you would have this as the first line of the derived implementation of func().