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I have a structure and a bidimensional array of those structs:
typedef struct {
char exit_n;
char exit_s;
char exit_w;
char exit_e;
} room;
room map[MAP_WIDTH][MAP_HEIGHT];
I need an array of pointers those structs. The following code compiles, but I don't get the wanted result. Any help? This is getting really confused to me, any explanation would be appreciated
room *rooms;
rooms = (room*)malloc(sizeof(room*) * ROOM_NUM);
[..]
rooms[n] = map[room_x][room_y];
[..]
224
It is not possible to create an array of pointer to structures.
To allocate a new person in the myperson argument, we use the following syntax: person * myperson = (person *) malloc(sizeof(person)); This tells the compiler that we want to dynamically allocate just enough to hold a person struct in memory and then return a pointer of type person to the newly allocated data.
We can create an array of pointers also dynamically using a double pointer. Once we have an array pointers allocated dynamically, we can dynamically allocate memory and for every row like method 2.
Actually, I think you want
room** rooms;
rooms = (room**)malloc(sizeof(room*) * ROOM_NUM);
[..]
rooms[n] = &map[room_x][room_y];
This gives you an array of pointers to your rooms.
175
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