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C# dictionary initializer compilation inconsistency

The following code compiles, but fails with a NullReferenceException:

class Test
{
    public Dictionary<string, string> Dictionary { get; set; }
}

static void Main(string[] args)
{
    var x = new Test
    {
        Dictionary =   // fails
        {
            { "key", "value" }, { "key2", "value2" }
        }
    };
}

If you replace the line marked 'fails' with the following, it works (as expected):

Dictionary = new Dictionary<string, string> 

Is there any purpose to the failing syntax--can it be used successfully in some other case? Or is this an oversight in the compiler?

like image 606
Ben M Avatar asked Sep 23 '09 19:09

Ben M


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2 Answers

No, it's not a mistake... it's a flaw in your understanding of initialization syntax :)

The idea of the

Dictionary = { ... }

is for cases where the caller has read access to a collection property, but not write access. In other words, situations like this:

class Test
{
    private readonly Dictionary<string, string> dictionary 
        = new Dictionary<string, string>();
    public Dictionary<string, string> Dictionary { get { return dictionary; } }
}

Basically it ends up being calls to Add, but without creating a new collection first. So this code:

Test test = new Test { Dictionary = { { "a", "b"}, {"c", "d" } };

is equivalent to:

Test tmp = new Test();
Dictionary<string, string> tmpDictionary = tmp.Dictionary;
tmpDictionary.Add("a", "b");
tmpDictionary.Add("c", "d");
Test test = tmp;

A good example of where this is useful is with the Controls collection for a UI. You can do this:

Form form = new Form
{
    Controls = 
    {
        new Button { Text = "Hi" }, 
        new TextBox { Text = "There" } 
    }
};

but you couldn't actually set the Controls property, because it's read-only.

like image 185
Jon Skeet Avatar answered Sep 30 '22 01:09

Jon Skeet


You can still use the syntax you want in a constructor:

Dictionary<string, string> dictionary = new Dictionary<string, string>
            {
                {"a", "b"},
                {"c", "d"}
            };
like image 23
IamIC Avatar answered Sep 29 '22 23:09

IamIC