I am trying to create a new thread each time Task.Factory.StartNew
is called. The question is how to run the code bellow without throwing the exception:
static void Main(string[] args)
{
int firstThreadId = 0;
Task.Factory.StartNew(() => firstThreadId = Thread.CurrentThread.ManagedThreadId);
for (int i = 0; i < 100; i++)
{
Task.Factory.StartNew(() =>
{
while (true)
{
Thread.Sleep(1000);
if (firstThreadId == Thread.CurrentThread.ManagedThreadId)
throw new Exception("The first thread is reused.");
}
});
}
Console.Read();
}
EDIT: the new code if you comment the first for
statement there is no problem. But if you have it, WOW, the message "Thread reused" is written to the console. Can you explain that because I am really confused.
static void Main(string[] args)
{
ConcurrentDictionary<int, int> startedThreads = new ConcurrentDictionary<int, int>();
for (int i = 0; i < 10; i++)
{
Task.Factory.StartNew(() =>
{
Task.Factory.StartNew(() =>
{
startedThreads.AddOrUpdate(Thread.CurrentThread.ManagedThreadId,
Thread.CurrentThread.ManagedThreadId, (a, b) => b);
}, TaskCreationOptions.LongRunning);
for (int j = 0; j < 100; j++)
{
Task.Factory.StartNew(() =>
{
while (true)
{
Thread.Sleep(10);
if (startedThreads.ContainsKey(
Thread.CurrentThread.ManagedThreadId))
Console.WriteLine("Thread reused");
}
}, TaskCreationOptions.LongRunning);
}
});
}
Console.Read();
}
If you specify TaskCreationOptions.LongRunning
when starting the task, that provides a hint to the scheduler, which the default scheduler takes as an indicator to create a new thread for the task.
It's only a hint - I'm not sure I'd rely on it... but I haven't seen any counterexamples using the default scheduler.
Adding to Jon Skeet's answer, if you want to guarantee that a new thread is created every time, you can write your own TaskScheduler
that creates a new thread.
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