If I have two yield return
methods with the same signature, the compiler does not seem to be recognizing them to be similar.
I have two yield return
methods like this:
public static IEnumerable<int> OddNumbers(int N)
{
for (int i = 0; i < N; i++)
if (i % 2 == 1) yield return i;
}
public static IEnumerable<int> EvenNumbers(int N)
{
for (int i = 0; i < N; i++)
if (i % 2 == 0) yield return i;
}
With this, I would expect the following statement to compile fine:
Func<int, IEnumerable<int>> generator = 1 == 0 ? EvenNumbers : OddNumbers; // Does not compile
I get the error message
Type of conditional expression cannot be determined because there is no implicit conversion between 'method group' and 'method group'
However, an explicit cast works:
Func<int, IEnumerable<int>> newGen = 1 == 0 ? (Func<int, IEnumerable<int>>)EvenNumbers : (Func<int, IEnumerable<int>>)OddNumbers; // Works fine
Am I missing anything or Is this a bug in the C# compiler (I'm using VS2010SP1)?
Note: I have read this and still believe that the first one should've compiled fine.
EDIT: Removed the usage of var
in the code snippets as that wasn't what I intended to ask.
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No. It is not a bug. It has nothing with yield
. The thing is that expression type method group
can be converted to delegate
type only when it is assigned directly like: SomeDel d = SomeMeth
.
C# 3.0 specification:
§6.6 Method group conversions
An implicit conversion (§6.1) exists from a method group (§7.1) to a compatible delegate type.
This is the only implicit conversion possible with method groups.
How ternary operator is evaluated in terms of types inferences:
A ? B : C
:
Make sure that either B
or C
can be implicitly cast to one another's type. For example A ? 5 : 6.0
will be double
because 5 can be implicitly cast to double
. Type of A
and B
in this case is method group
and there is no conversion between method group
. Only to delegate and it can be enforced as you did.
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