Could someone please explain the following compiler error to me:
struct B
{
};
template <typename T>
struct A : private T
{
};
struct C : public A<B>
{
C(A<B>); // ERROR HERE
};
The error at the indicated line is:
test.cpp:2:1: error: 'struct B B::B' is inaccessible
test.cpp:12:7: error: within this context
What exactly is inaccessible, and why?
Try A< ::B>
or A<struct B>
.
Inside of C
, unqualified references to B
will pick up the so-called injected-class-name, it is brought in through the base class A
. Since A
inherits privately from B
, the injected-class-name follows suit and will also be private, hence be inaccessible to C
.
Another day, another language quirk...
The problem is name shielding of struct B . Check it out:
struct B{};
struct X{};
template <class T>
struct A : private T
{};
struct C : public A<B>
{
C(){
A<X> t1; // WORKS
// A<B> t2; // WRONG
A< ::B> t3; // WORKS
}
};
int main () {
}
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