Is there a way in python to obtain the covariance matrix given the mean and sample data points
Example:
mean = [3 3.6]
data = [[1 2]
[2 3]
[3 3]
[4 5]
[5 5]]
I know how to calculate the same by substituting these values in the formula. But is there a build in function in python which does this for me. I know there is one in Matlab, but I am not sure about python.
Covariance is calculated by analyzing at-return surprises (standard deviations from the expected return) or by multiplying the correlation between the two random variables by the standard deviation of each variable.
The covariance may be computed using the Numpy function np. cov() . For example, we have two sets of data x and y , np. cov(x, y) returns a 2D array where entries [0,1] and [1,0] are the covariances.
The covariance matrix is given by Σ=(Var(X1)Cov(X1,X2)Cov(X2,X1)Var(X2)). Since Cov(X1,X2)=Cov(X2,X1), only three entries have to be estimated.
We wish to find out covariance in Excel, that is, to determine if there is any relation between the two. The relationship between the values in columns C and D can be calculated using the formula =COVARIANCE. P(C5:C16,D5:D16).
numpy.cov()
can be used to compute the covariance matrix:
In [1]: import numpy as np
In [2]: data = np.array([[1,2], [2,3], [3,3], [4,5], [5,5]])
In [3]: np.cov(data.T)
Out[3]:
array([[ 2.5, 2. ],
[ 2. , 1.8]])
By default, np.cov()
expects each row to represent a variable, with observations in the columns. I therefore had to transpose your matrix (by using .T
).
An alternative way to achieve the same thing is by setting rowvar
to False
:
In [15]: np.cov(data, rowvar=False)
Out[15]:
array([[ 2.5, 2. ],
[ 2. , 1.8]])
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With