Bootstrap-vue b-table with filter in header

Question

I have a table generated with bootstrap-vue that shows the results of a system search.

The Results Table shows the records to the user, and the user can sort them and filter them.

How can I add the search field underneath the table header <th> generated with the bootstrap-vue <b-table> element?

Screenshot of the current table:

Mockup of the wanted table:

Answer 1

You can use the top-row slot to customise your own first-row. See below for a bare-bones example.

new Vue({
  el: '#app',
  data: {
    filters: {
      id: '',
      issuedBy: '',
      issuedTo: ''
    },
    items: [{id:1234,issuedBy:'Operator',issuedTo:'abcd-efgh'},{id:5678,issuedBy:'User',issuedTo:'ijkl-mnop'}]
  },
  computed: {
    filtered () {
      const filtered = this.items.filter(item => {
        return Object.keys(this.filters).every(key =>
            String(item[key]).includes(this.filters[key]))
      })
      return filtered.length > 0 ? filtered : [{
        id: '',
        issuedBy: '',
        issuedTo: ''
      }]
    }
  }
})

<link type="text/css" rel="stylesheet" href="//unpkg.com/bootstrap/dist/css/bootstrap.min.css"/><link type="text/css" rel="stylesheet" href="//unpkg.com/bootstrap-vue@latest/dist/bootstrap-vue.css"/><script src="https://cdn.jsdelivr.net/npm/[email protected]/dist/vue.min.js"></script><script src="//unpkg.com/babel-polyfill@latest/dist/polyfill.min.js"></script><script src="//unpkg.com/bootstrap-vue@latest/dist/bootstrap-vue.js"></script>

<div id="app">
<b-table striped show-empty :items="filtered">
  <template slot="top-row" slot-scope="{ fields }">
    <td v-for="field in fields" :key="field.key">
      <input v-model="filters[field.key]" :placeholder="field.label">
    </td>
  </template>
</b-table>
</div>

Note: I've used a computed property to filter the items instead of the :filter prop in b-table because it doesn't render rows if all the items are filtered out, including your custom first-row. This way I can provide a dummy data row if the result is empty.

Answer 2

Have upvoted phil's answer, just making it more generic

filtered() {
      const filtered = this.items.filter(item => {
        return Object.keys(this.filters).every(key =>
          String(item[key]).includes(this.filters[key])
        );
      });
      return filtered.length > 0
        ? filtered
        : [
            Object.keys(this.items[0]).reduce(function(obj, value) {
              obj[value] = '';
              return obj;
            }, {})
          ];
    }