Is it possible to set minimum and maximum limit of a value (suppose it is unsigned short and I need a value between 0 and 10) as I can set default value by
opt::value<unsigned short>()->default_value(5)
I want to use arguments given from variables map of program options immediately without checking each of them.
I recommend a lambda (like kaveish's answer). But you can have it return a function that checks the appropriate bounds to make everything more readable.
auto in = [](int min, int max, char const * const opt_name){
  return [opt_name, min, max](unsigned short v){ 
    if(v < min || v > max){ 
      throw opt::validation_error
        (opt::validation_error::invalid_option_value,
         opt_name, std::to_string(v));
    }
  };
};
opt::value<unsigned short>()->default_value(5)
  ->notifier(in(0, 10, "my_opt"));
                        In C++11 this can also be achieved using lambda expressions.
opt::value<unsigned short>()
  ->default_value(5)
  ->notifier(
      [](std::size_t value)
      {
        if (value < 0 || value > 10) {
          // throw exception
        }
      })
This handily keeps the validation code itself close to the call point and allows you to customize the exception easier, something like
throw opt::validation_error(
  opt::validation_error::invalid_option_value,
  "option_name",
  std::to_string(value));
                        No, you cannot. All options are described here. You can check them manually, or write function, that will check them manually.
opt::value<unsigned short>()->default_value(5)->notifier(&check_function);
where check function is something like
void check(unsigned short value)
{
   if (value < 0 || value > 10)
   {
      // throw exception
   }
}
or more general
template<typename T>
void check_range(const T& value, const T& min, const T& max)
{
   if (value < min || value > max)
   {
      // throw exception
   }
}
opt::value<unsigned short>()->default_value(5)->notifier
(boost::bind(&check_range<unsigned short>, _1, 0, 10));
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