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How do you perform a bitwise AND operation on two 32-bit integers in C#?
Most common C# bitwise operations.
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The & (bitwise AND) in C or C++ takes two numbers as operands and does AND on every bit of two numbers. The result of AND is 1 only if both bits are 1. The | (bitwise OR) in C or C++ takes two numbers as operands and does OR on every bit of two numbers. The result of OR is 1 if any of the two bits is 1.
A bitwise OR is a binary operation that takes two bit patterns of equal length and performs the logical inclusive OR operation on each pair of corresponding bits. The result in each position is 0 if both bits are 0, while otherwise the result is 1. For example: 0101 (decimal 5) OR 0011 (decimal 3) = 0111 (decimal 7)
XOR is a bitwise operator, and it stands for "exclusive or." It performs logical operation. If input bits are the same, then the output will be false(0) else true(1).
The bitwise AND operator ( & ) returns a 1 in each bit position for which the corresponding bits of both operands are 1 s.
With the & operator
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Use the & operator.
Binary & operators are predefined for the integral types[.] For integral types, & computes the bitwise AND of its operands.
From MSDN.
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