Binary operator '..<' cannot be applied to operands of type 'Int' and 'CGFloat'

Question

I'm trying to create a for loop but can't seem to understand how to get rid of this error

My code:

for i:CGFloat in 0 ..< 2 + self.frame.size.width / (movingGroundTexture.size().width) { 
        let sprite = SKSpriteNode(texture: movingGroundTexture)
        sprite.zPosition = 0
        sprite.anchorPoint = CGPointMake(0, 0)
        sprite.position = CGPointMake(i * sprite.size.width, 0)
        addChild(sprite)
    }

The error is on for line on self.frame.size.width and (movingGroundTexture.aize().width)

Answer 1

You cannot create a CountableRange (or CountableClosedRange) with floating point types.

You either want to convert your 2 + self.frame.size.width / movingGroundTexture.size().width to an Int:

for i in 0 ..< Int(2 + self.frame.size.width / movingGroundTexture.size().width) { 
    // i is an Int      
}

Or you want to use stride (Swift 2 syntax):

for i in CGFloat(0).stride(to: 2 + self.frame.size.width / movingGroundTexture.size().width, by: 1) { 
    // i is a CGFloat   
}

Swift 3 syntax:

for i in stride(from: 0, to: 2 + self.frame.size.width / movingGroundTexture.size().width, by: 1) {
    // i is a CGFloat
}

Depends on whether you need floating point precision or not. Note that if your upper bound is a non-integral value, the stride version will iterate one more time than the range operator version, due to the fact that Int(...) will ignore the fractional component.

Answer 2

You have to convert the right side of the range to an integer type, like Int or UInt:

for i in 0 ..< Int(2 + self.frame.size.width / (movingGroundTexture.size().width)) {
    ...
}