Best way to programmatically detect iPad/iPhone hardware

Question

The reason I need to find out is that on an iPad, a UIPickerView has the same height in landscape orientation as it does in portrait. On an iPhone it is different. The iPad programming guide introduces an "idiom" value to UIDevice:

    UIDevice* thisDevice = [UIDevice currentDevice];     if(thisDevice.userInterfaceIdiom == UIUserInterfaceIdiomPad)     {         // iPad     }     else     {         // iPhone     } 

which works OK while you're in iPad (3.2) but not iPhone (3.1.3) - so it looks like there also needs to be an ifdef to conditionally compile that check, like:

#if __IPHONE_OS_VERSION_MIN_REQUIRED >= 30200         UIDevice* thisDevice = [UIDevice currentDevice];         if(thisDevice.userInterfaceIdiom == UIUserInterfaceIdiomPad)         {             // etc.         } #endif 

To me that's starting to look very clumsy. What's a better way?

Answer 1

Checking at runtime (your first way) is completely different from #if at compile time. The preprocessor directives won't give you a universal app.

The preferred way is to use Apple's Macro:

if (UI_USER_INTERFACE_IDIOM() == UIUserInterfaceIdiomPad) {      // The device is an iPad running iPhone 3.2 or later. } else {      // The device is an iPhone or iPod touch. } 

Use 3.2 as the base SDK (because the macro is not defined pre 3.2), you can target prior OS versions to get it running on the iPhone.