Best way to find os name and version in Unix/Linux platform

Question

I need to find the OS name and version on Unix/Linux platform. For this I tried following:

1. lsb_release utility

2. /etc/redhat-release or specific file

But it does not seem to be best solution as LSB_RELEASE support is no longer for RHEL 7.

Is there any way that will work on any Unix or Linux platform?

Answer 1

This work fine for all Linux environment.

#!/bin/sh
cat /etc/*-release

In Ubuntu:

$ cat /etc/*-release
DISTRIB_ID=Ubuntu
DISTRIB_RELEASE=10.04
DISTRIB_CODENAME=lucid
DISTRIB_DESCRIPTION="Ubuntu 10.04.4 LTS"

or 12.04:

$ cat /etc/*-release

DISTRIB_ID=Ubuntu
DISTRIB_RELEASE=12.04
DISTRIB_CODENAME=precise
DISTRIB_DESCRIPTION="Ubuntu 12.04.4 LTS"
NAME="Ubuntu"
VERSION="12.04.4 LTS, Precise Pangolin"
ID=ubuntu
ID_LIKE=debian
PRETTY_NAME="Ubuntu precise (12.04.4 LTS)"
VERSION_ID="12.04"

In RHEL:

$ cat /etc/*-release
Red Hat Enterprise Linux Server release 6.5 (Santiago)
Red Hat Enterprise Linux Server release 6.5 (Santiago)

Or Use this Script:

#!/bin/sh
# Detects which OS and if it is Linux then it will detect which Linux
# Distribution.

OS=`uname -s`
REV=`uname -r`
MACH=`uname -m`

GetVersionFromFile()
{
    VERSION=`cat $1 | tr "\n" ' ' | sed s/.*VERSION.*=\ // `
}

if [ "${OS}" = "SunOS" ] ; then
    OS=Solaris
    ARCH=`uname -p` 
    OSSTR="${OS} ${REV}(${ARCH} `uname -v`)"
elif [ "${OS}" = "AIX" ] ; then
    OSSTR="${OS} `oslevel` (`oslevel -r`)"
elif [ "${OS}" = "Linux" ] ; then
    KERNEL=`uname -r`
    if [ -f /etc/redhat-release ] ; then
        DIST='RedHat'
        PSUEDONAME=`cat /etc/redhat-release | sed s/.*\(// | sed s/\)//`
        REV=`cat /etc/redhat-release | sed s/.*release\ // | sed s/\ .*//`
    elif [ -f /etc/SuSE-release ] ; then
        DIST=`cat /etc/SuSE-release | tr "\n" ' '| sed s/VERSION.*//`
        REV=`cat /etc/SuSE-release | tr "\n" ' ' | sed s/.*=\ //`
    elif [ -f /etc/mandrake-release ] ; then
        DIST='Mandrake'
        PSUEDONAME=`cat /etc/mandrake-release | sed s/.*\(// | sed s/\)//`
        REV=`cat /etc/mandrake-release | sed s/.*release\ // | sed s/\ .*//`
    elif [ -f /etc/debian_version ] ; then
        DIST="Debian `cat /etc/debian_version`"
        REV=""

    fi
    if [ -f /etc/UnitedLinux-release ] ; then
        DIST="${DIST}[`cat /etc/UnitedLinux-release | tr "\n" ' ' | sed s/VERSION.*//`]"
    fi

    OSSTR="${OS} ${DIST} ${REV}(${PSUEDONAME} ${KERNEL} ${MACH})"

fi

echo ${OSSTR}

Answer 2

Following command worked out for me nicely. It gives you the OS name and version.

lsb_release -a

Answer 3

The "lsb_release" command provides certain Linux Standard Base and distribution-specific information. So using the below command we can get Operating system name and operating system version.

"lsb_release -a"