The concatenation of vectors can be done by using combination function c. For example, if we have three vectors x, y, z then the concatenation of these vectors can be done as c(x,y,z). Also, we can concatenate different types of vectors at the same time using the same same function.
Vector is a module in Rust that provides the container space to store values. It is a contiguous resizable array type, with heap-allocated contents. It is denoted by Vec<T>. Vectors in Rust have O(1) indexing and push and pop operations in vector also take O(1) complexity.
In Rust, there are several ways to initialize a vector. In order to initialize a vector via the new() method call, we use the double colon operator: let mut vec = Vec::new();
The structure std::vec::Vec
has method append()
:
fn append(&mut self, other: &mut Vec<T>)
Moves all the elements of
other
intoSelf
, leavingother
empty.
From your example, the following code will concatenate two vectors by mutating a
and b
:
fn main() {
let mut a = vec![1, 2, 3];
let mut b = vec![4, 5, 6];
a.append(&mut b);
assert_eq!(a, [1, 2, 3, 4, 5, 6]);
assert_eq!(b, []);
}
Alternatively, you can use Extend::extend()
to append all elements of something that can be turned into an iterator (like Vec
) to a given vector:
let mut a = vec![1, 2, 3];
let b = vec![4, 5, 6];
a.extend(b);
assert_eq!(a, [1, 2, 3, 4, 5, 6]);
// b is moved and can't be used anymore
Note that the vector b
is moved instead of emptied. If your vectors contain elements that implement Copy
, you can pass an immutable reference to one vector to extend()
instead in order to avoid the move. In that case the vector b
is not changed:
let mut a = vec![1, 2, 3];
let b = vec![4, 5, 6];
a.extend(&b);
assert_eq!(a, [1, 2, 3, 4, 5, 6]);
assert_eq!(b, [4, 5, 6]);
I can't make it in one line. Damian Dziaduch
It is possible to do it in one line by using chain()
:
let c: Vec<i32> = a.into_iter().chain(b.into_iter()).collect(); // Consumed
let c: Vec<&i32> = a.iter().chain(b.iter()).collect(); // Referenced
let c: Vec<i32> = a.iter().cloned().chain(b.iter().cloned()).collect(); // Cloned
let c: Vec<i32> = a.iter().copied().chain(b.iter().copied()).collect(); // Copied
There are infinite ways.
Regarding the performance, slice::concat
, append
and extend
are about the same. If you don't need the results immediately, making it a chained iterator is the fastest; if you need to collect()
, it is the slowest:
#![feature(test)]
extern crate test;
use test::Bencher;
#[bench]
fn bench_concat___init__(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
});
}
#[bench]
fn bench_concat_append(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.append(&mut y)
});
}
#[bench]
fn bench_concat_extend(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.extend(y)
});
}
#[bench]
fn bench_concat_concat(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
[x, y].concat()
});
}
#[bench]
fn bench_concat_iter_chain(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.into_iter().chain(y.into_iter())
});
}
#[bench]
fn bench_concat_iter_chain_collect(b: &mut Bencher) {
b.iter(|| {
let mut x = vec![1i32; 100000];
let mut y = vec![2i32; 100000];
x.into_iter().chain(y.into_iter()).collect::<Vec<i32>>()
});
}
running 6 tests
test bench_concat___init__ ... bench: 27,261 ns/iter (+/- 3,129)
test bench_concat_append ... bench: 52,820 ns/iter (+/- 9,243)
test bench_concat_concat ... bench: 53,566 ns/iter (+/- 5,748)
test bench_concat_extend ... bench: 53,920 ns/iter (+/- 7,329)
test bench_concat_iter_chain ... bench: 26,901 ns/iter (+/- 1,306)
test bench_concat_iter_chain_collect ... bench: 190,334 ns/iter (+/- 16,107)
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