Batch File input validation - Make sure user entered an integer

Question

I'm experimenting with a Windows batch file to perform a simple operation which requires the user to enter a non-negative integer. I'm using simple batch-file techniques to get user input:

@ECHO OFF
SET /P UserInput=Please Enter a Number: 

The user can enter any text they want here, so I would like to add some routine to make sure what the user entered was a valid number. That is... they entered at least one character, and every character is a number from 0 to 9. I'd like something I can feed the UserInput into. At the end of the routine would be like an if/then that would run different statements based on whether or not it was actually a valid number.

I've experimented with loops and substrings and such, but my knowledge and understanding is still slim... so any help would be appreciated.

I could build an executable, and I know there are nicer ways to do things than batch files, but at least for this task I'm trying to keep it simple by using a batch file.

Answer 1

You're probably not doing this in a DOS batch file. Or at least, support for set /p is unheard of for me in DOS :-)

You could use substrings. In fact I have written a parser for a specific regular language that way once, but it's cumbersome. The easiest way would probably be to assign the contents of %userinput% to another variable, using set /a. If the result comes out as 0 you need to check whether the input itself was 0, otherwise you can conclude it was a non-number:

@echo off
setlocal enableextensions enabledelayedexpansion
set /p UserInput=Enter a number: 
set /a Test=UserInput
if !Test! EQU 0 (
  if !UserInput! EQU 0 (
    echo Number
  ) else (
    echo Not a number
  )
) else (
  echo Number
)

However, this works only for numbers in the range of Int32. If you just care for any number (possibly floating-point as well) then you need to resort to the loop-based approach of dissecting it.

NOTE: Updated to solve the space issues. However, there is still a problem lurking: Entering 123/5 yields "number", since set /a can evaluate this ...

Answer 2

Thanks all. I was trying to make it harder for myself looking at loops and string manipulation. I used your tips on math evaluation and comparison. Here's what I finally came up with as my concept script:

:Top
@ECHO OFF
ECHO.
ECHO ---------------------------------------
SET /P UserInput=Please Enter a Number: 
ECHO.
ECHO UserInput = %UserInput%
ECHO.
SET /A Evaluated=UserInput
ECHO Math-Evaluated UserInput = %Evaluated%
if %Evaluated% EQU %UserInput% (
    ECHO Integer
    IF %UserInput% GTR 0 ( ECHO Positive )
    IF %UserInput% LSS 0 ( ECHO Negative )
    IF %UserInput% EQU 0 ( ECHO Zero )
    REM - Other Comparison operators for numbers
    REM - LEQ - Less Than or Equal To
    REM - GEQ - Greater Than or Equal To
    REM - NEQ - Not Equal To
) ELSE (
    REM - Non-numbers and decimal numbers get kicked out here
    ECHO Non-Integer
)

GOTO Top

This method catches all numbers and can detect whether it's positive, negative, or zero. Any decimal or string will be detected as non-integers. The only edge case I've found is a string with spaces. For example, the text "Number 1" will cause the script to crash/close when the user input is evaluated as math. But in my situation, this is fine. I don't want my script to go on with invalid input.