Bash string to array with IFS

Question

I'm having trouble using the IFS to convert my string into an array. Here is what I have as my string:

"Jun01 Jun02 Jun03 Jun04 Jun05 ..." #in that format, separated by spaces

And here is the code I have tried:

IFS=" " #set it to space character
DATES_ARRAY=($DATES_STRING) #from above
echo ${DATES_ARRAY[0]} #output is empty

However when I remove the IFS line it works. But I used a few lines to print out its default ASCII value and I got '32' which means 'Space' character. Being an OCD programmer I'd like to set it myself just to be safe... I don't know how it's going to be preset a priori!

So why does trying to set IFS to Space manually not work?

Answer 1

It does work, but it's unnecessary anyway because space is guaranteed to be in IFS by default. Don't set it manually. Doing so can cause problems.

Basically, never use word-splitting in Bash. Sometimes it's required to bite the bullet and use it if restricted to POSIX sh, if used very carefully. If you're going to set IFS, set it in the environment of one of the few commands where it has some effect, or at the very most, locally to a function.

You'll never need to use this so I won't explain everything:

$ printf -v str '%s ' Jun{01..10}
$ set -f
$ IFS=' ' declare -a 'arr=($str)'
$ declare -p arr
declare -a arr='([0]="Jun01" [1]="Jun02" [2]="Jun03" [3]="Jun04" [4]="Jun05" [5]="Jun06" [6]="Jun07" [7]="Jun08" [8]="Jun09" [9]="Jun10")'

IFS set to space here redundantly to show it works.

Probably the most correct way to go from a string to an array is to use read. Many examples here.

The cannonical method is:

read -ra arr <<<"$str"

where IFS is optionally set in the environment of read to act as a delimiter if it's something other than whitespace.