Bash sleep in milliseconds

Question

I need a timer which will work with milliseconds. I tried to use sleep 0.1 command in a script, but I see this error message:

syntax error: invalid arithmetic operator (error token is ".1")

When I run sleep 0.1 in terminal it works fine.

Please help me!

EDIT: Sorry I have made a mistake:

function timer { while [[ 0 -ne $SECS ]]; do     echo "$SECS.."     sleep 0.1     SECS=$[$SECS-0.1] done } 

Line sleep 0.1 was 5th and SECS=$[$SECS-0.1] was 6th. I just garbled lines. The problem was in 6th line, because bash can't work with float numbers. I changed my function as below:

MS=1000 function timer { while [[ 0 -ne $MS ]]; do     echo "$SECS.."     sleep 0.1     MS=$[$MS-100] done } 

Answer 1

Make sure you're running your script in Bash, not /bin/sh. For example:

#!/usr/bin/env bash sleep 0.1 

In other words, try to specify the shell explicitly. Then run either by: ./foo.sh or bash foo.sh.

In case, sleep is an alias or a function, try replacing sleep with \sleep.

Answer 2

Some options:

read -p "Pause Time .5 seconds" -t 0.5 

or

read -p "Continuing in 0.5 Seconds...." -t 0.5 echo "Continuing ...."