Bash shell script run on UNIX command line does not change the current shell environment [duplicate]

Question

Possible Duplicate:
Why doesn't “cd” work in a bash shell script?

I'm attempting to execute a bash shell script './go_cd' from the UNIX command line in my working directory '/c/My_Objective'. All I expect the script to do is change to a new directory '/c/My_Objective/project'. The script output indicates that the directory has been changed to '/c/My_Objective/project, however when the script completes execution and returns to the current command line, the directory is still at '/c/My_Objective'. Why was the directory not changed?

Below is the simple Bash shell script that I'm using as a test.

#!/bin/bash
## current directory is '/c/My_Objective'
pwd
cd project
## new directory should now be '/c/My_Objective/project'
pwd

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Is there a way to get the commands, ie., 'cd', executing in the new script process get passed back to the original process where I started 'go_cd' script execution?

Winston

Answer 1

Subprocesses don't affect the parent process. If you want your shell script to modify the existing shell, it has to be run by the existing shell, something like:

. myscript.sh