Bash script to watch execution time of other scripts

Question

I have a main script which run all the scripts in a folder.

#!/bin/bash
for each in /some_folder/*.sh
do
  bash $each
done;

I want to know if execution of one of them lasts too long (more than N seconds). For example execution of script such as:

#!/bin/bash
ping -c 10000 google.com

will lasts very long, and I want my main script to e-mail me after N second.

All I can do now is to run all scripts with #timeout N option but it stops them! Is it possible to E-mail me and not to stop execution of script?

Answer 1

Try this :

#!/bin/bash

# max seconds before mail alert
MAX_SECONDS=3600

# running the command in the background and get the pid
command_that_takes_a_long_time & _pid=$!

sleep $MAX_SECONDS

# if the pid is alive...
if kill &>/dev/null -0 $_pid; then
    mail -s "script $0 takes more than $MAX_SECONDS" [email protected] < /dev/null
fi

We run the command in the background, then sleep for MAX_SECONDS in // and alert by email if the process takes more than what is permitted.

Finally, with your specific requirements :

#!/bin/bash

MAX_SECONDS=3600

alerter(){
    bash "$1" & _pid=$!
    sleep $MAX_SECONDS
    if kill &>/dev/null -0 $_pid; then
        mail -s "$2 takes more than $MAX_SECONDS" [email protected] < /dev/null
    fi
}

for each in /some_folder/*.sh; do
    alerter "$each" &
    wait $_pid # remove this line if you wou'd like to run all scripts in //
done