Bash Script - store find command output without spaces in variable

Question

I am looking to automate my xcode projects. It all works fine except the projects name with spaces. I have tried the following commands:

output_apps=`find ./ -name "*.app" -print`
output_apps=`find ./ -name "*.app"`

When I run

find ./ -name "*.app" -print 

without storing into variable, it gives me output as expected as mentioned below:

.//Ten EU.app
.//Ten Official App EU.app
.//Ten Official App.app
.//Ten.app

However when I store the output of above command in a variable as below

output_apps=`find ./ -name "*.app" -print`

and then run the following for loop for get the names

for curr_app in $o
do 
    echo "$curr_app"
done

It shows

.//Ten
EU.app
.//Ten
Official
App
EU.app
.//Ten
Official
App.app
.//Ten.app

How do I maintain the spaces between each output and get the following output?

Ten EU.app
Ten Official App EU.app
Ten Official App.app
Ten.app

Answer 1

If you don't need to store the file names in a variable, you can use find -print0 in combination with xargs -0. This separates the found entries by NUL bytes instead of newlines. xargs reads these NUL separated values and calls some command with as many arguments as possible.

find ./ -name "*.app" -print0 | xargs -0 some-command

If you want, you can limit the number of arguments given to some-command with xargs -n 1

find ./ -name "*.app" -print0 | xargs -0 -n 1 some-command

Yet another approach is to read the files with a while loop

find ./ -name "*.app" -print | while read f; do
    some-command "$f"
done

This calls some command with one file at a time. The important point is to enclose the $f into double quotes.