Bash: Save and print arguments from an array

Question

How do you save all the arguments in a bash script to an array and print them individually?

Answer 1

Initialize the array:

ARGS=("$@")              # "$@" gives the arguments passed to the script
ARGS=(arg1 arg2 arg3)    # or fill the array out yourself

Display the array items:

for ARG in "${ARGS[@]}"; do
    printf '%s\n' "$ARG"
done