BASH - Only printing the deepest directory in path

Question

I need some help.....

In my .bashrc file I have a VERY useful function (It may be a bit rough and ready, and a bit hacky, but it works a treat!) that reads an input file, and uses the 'tree' function on each of the input lines to create a directory tree. this tree is then printed into an output file (along with the size of the folder).

multitree()
{
    while read cheese
    do
        pushd . > /dev/null
        pushd $cheese > /dev/null
        echo -e "$cheese \n\n" >> ~/Desktop/$2.txt
        tree -idf . >> ~/Desktop/$2.txt
        echo -e "\n\n\n" >> ~/Desktop/$2.txt
        du -sh --si >> ~/Desktop/$2.txt
        echo -e "\n\n\n\n\n\n\n" >> ~/Desktop/$2.txt
        popd > /dev/null
    done < $1
        cat ~/done
}

This is a time saver like no end, and outputs a snippet like the following:

./foo
./foo/bar
./foo/bar/1
./foo/bar/1/2

etc etc....

however, the first (and most tedious) thing I need to do is remove all entries leaving only the deepest folder path (Using the above example it would be reduced to just ./foo/bar/1/2)

Is there a way of processing the file before/after the tree function to only print the deepest levels?

I know something like python might do a better job, but my issue is I've never used python And I'm not sure the work systems would let me run python... they let us modify our own .bashrc so I'm not too worried!

Thanks in advance guys!!!!

Owen.

Answer 1

You could use

find . -type d -links 2

Replace . with a directory if desired.

EDIT: Explanation:

find searches a directory for files that match a given filter. In this case, the directory is ., and the filter is -type d -links 2.

-type d filters for directories

-links 2 filters for those that have two (hard) links to their name. Effectively, this filters for all directories that have no subdirectories, because only those have two: The one in their parent directory and the . link in themselves. Those with subdirectories also have the .. links in their subdirectories.