Bash One Liner: copy template_*.txt to foo_*.txt?

Question

Say I have three files (template_*.txt):

• template_x.txt
• template_y.txt
• template_z.txt

I want to copy them to three new files (foo_*.txt).

• foo_x.txt
• foo_y.txt
• foo_z.txt

Is there some simple way to do that with one command, e.g.

cp --enableAwesomeness template_*.txt foo_*.txt

Answer 1

for f in template_*.txt; do cp $f foo_${f#template_}; done

Answer 2

[01:22 PM] matt@Lunchbox:~/tmp/ba$
ls
template_x.txt  template_y.txt  template_z.txt

[01:22 PM] matt@Lunchbox:~/tmp/ba$
for i in template_*.txt ; do mv $i foo${i:8}; done

[01:22 PM] matt@Lunchbox:~/tmp/ba$
ls
foo_x.txt  foo_y.txt  foo_z.txt

Answer 3

My preferred way:

for f in template_*.txt
do
  cp $f ${f/template/foo}
done

The "I-don't-remember-the-substitution-syntax" way:

for i in x y z
do
  cp template_$i foo_$
done

Answer 4

This should work:

for file in template_*.txt ; do cp $file `echo $file | sed 's/template_\(.*\)/foo_\1/'` ; done

Answer 5

for i in template_*.txt; do cp -v "$i" "`echo $i | sed 's%^template_%foo_%'`"; done

Probably breaks if your filenames have funky characters in them. Remove the '-v' when (if) you get confidence that it works reliably.