Bash: How to show full list of job processes and kill them

Question

I issue a command task1 & task2 dir/ && task3 &

• Task1 never ends, so we send it to the background.
• Task2 changes the directory
• Task3 depends on task2 completing.

Issuing: jobs -l will show:

[1]- 39281 Running                 task1 &
[2]+ 39282 Running                 task2 && task3 &

Issuing: ps will show:

39281 ttys002    0:04.17 task1  
39282 ttys002    0:00.00 task2
39283 ttys002    0:03.66 task3

Questions:

1. Is there a way to show task3 in the jobs command output?
2. Why doesn't task3 show up as a its own job?
3. Is there a way to kill all three tasks simultaneously?
4. Why doesn't task3 die if I kill task2?
5. Is there a better way to do this?

Goal: Issue a single line of commands to init a workflow and send it to the background. When ready kill all started processes in one go.

For context and in my case, task1 is a grunt task with livereload, so it should be sent to the background. Task2 changes the directory so that task3 can watch files changed in that directory.

Answer 1

Using bash with job control you can kill the most recent two background tasks more-or-less simultaneously with

kill %% %-

If you want the job not to show the cd part you'll need to change the directory in the current shell, which means isolating the cd expression:

sleep 10000 & cd .. && { sleep 20000 & }