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I cannot pinpoint the exact difference between using ${array[@]} vs ${array[*]}
What diff I see is when printing, but I guess there is more to it
declare -a array
array=("1" "2" "3")
IFS=","
printf "%s" ${array[@]}
printf "%s" ${array[*]}
IFS=" "
I searched on TLDP about it, but couldn't figure it out. Is it a general bash thing or just for arrays? Thanks a lot!
376
The operator "%" will try to remove the shortest text matching the pattern, while "%%" tries to do it with the longest text matching.
(difference) [[ is a keyword. [[ is a shell keyword (invoke type [[ in Bash to confirm this). Like the [ builtin, the [[ keyword belongs to Bash; but it does not behave like a command. (similarity) [[ requires a space after.
As mentioned in man bash:
If the word is double-quoted,
${name[*]}expands to a single word with the value of each array member separated by the first character of theIFSspecial variable, and${name[@]}expands each element of name to a separate word.
Examples:
array=("1" "2" "3")
printf "'%s'" "${array[*]}"
'1 2 3'
printf "'%s'" "${array[@]}"
'1''2''3'
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