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Bad URL when requesting with NSURL

I'm trying to request this kind of URL in iPhone 4.0 SDK (access token slightly modified because you don't really need to see it):

https://graph.facebook.com/me?sdk=ios&sdk_version=2&access_token=123902817987|8cb9e8408d2685cef853cd80.9-747882379|UGu5NvcAHiXuGEGzkq&format=json&limit=40&until=1286619821

But I got this message:

Failed with error: Error Domain=NSURLErrorDomain Code=-1000 "bad URL" UserInfo=0x9e657a0 {NSUnderlyingError=0x9e656a0 "bad URL", NSLocalizedDescription=bad URL}

When I copied and pasted in Safari or Chrome, it works. I tried replacing | with %| as suggested here but doesn't work.

Asking it from the terminal looks like this:

curl https://graph.facebook.com/me/statuses?sdk=ios&sdk_version=2&access_token=9999955817987|8ab9e8408d2685cef.3-747882379|UGuxWDuM&format=json&limit=40&until=1286619821
[1] 16190
[2] 16191
[3] 16194
[4] 16195
[5] 16196
[2]   Done                    sdk_version=2
[4]-  Done                    format=json
$ -bash: UGu5NvcAHiXuGEGzkq3KP8xWDuM: command not found
-bash: 8ab9e8408d2685cef853cd80.3-747882379: command not found
{"error":{"type":"OAuthException","message":"An active access token must be used to query information about the current user."}}
[1]   Done                    curl https://graph.facebook.com/me/statuses?sdk=ios
[3]-  Exit 127                access_token=9999955817987 | 8ab9e8408d2685cef.3-747882379 | UGuxWDuM
[5]+  Done                    limit=40

Any ideas?

like image 406
Enrico Susatyo Avatar asked Jun 09 '11 01:06

Enrico Susatyo


2 Answers

 NSString *strURL = [loc_address stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

            // requesting weather for this location ... 
            NSMutableURLRequest *req = [[NSMutableURLRequest alloc] initWithURL:[NSURL URLWithString:[NSString stringWithFormat: @"http://www.google.com/ig/api?weather=%@", strURL]] cachePolicy:NSURLRequestUseProtocolCachePolicy timeoutInterval:5.0];
            [req setHTTPMethod:@"POST"];
            [req addValue:@"text/xml; charset=utf-8" forHTTPHeaderField:@"Content-Type"];
like image 72
YogiAR Avatar answered Sep 28 '22 16:09

YogiAR


You need to replace the pipe character in the URL with %7C. This is the URL encoded value.

Also, the URL needs to be enclosed in quotation marks in order for it to work with curl.

like image 32
csano Avatar answered Sep 28 '22 18:09

csano