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Axios recursion for paginating an api with a cursor

How can I paginate an API with a cursor using axios? I would like to recursively call this function until response.data.length < 1 and return the entire array with all items in the collection when it is done. Also, worth noting, I would have to pass the cursor into subsequent calls.

function getUsers () {
    return axios.get('/users') // API supports a cursor param (?after=)
             .then(response => {
               // returns an array with a cursor
               // see response below
               console.log(response.data)
             })
}

Example response:

{
    "total": 100,
    "data": [
        {
            user: "Bob"
        },
        {
            user: "Sue"
        },
        {
            user: "Mary"
        },
    ],
    "pagination": {
        "cursor": "lkdjsfkljsdkljfklsdjfkjsdk"
    }
}

Thank you for your help in advance.

like image 528
TechnoTim Avatar asked Jul 25 '18 04:07

TechnoTim


2 Answers

Here's a recursive function that manages the cursor from the response:

function getUsers (cursor, data = []) {
    return axios.get('/users' + (cursor ? '?after='+cursor : '')) // API supports a cursor param (?after=)
      .then(response => {
          if (response.data.length < 1 ) return data
          data.push(...response.data)
          return getUsers(response.pagination.cursor, data)
      })
}
// use it to get data
getUsers()
.then(data => console.log("final data", data))

This is how it might work with a faked axios function and some extra logging to show the ordering:

// Fake axios get -- just return numbers so it's easy to test
let axios = {
    data: data = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15],
    get(url) {
        let cursor = parseInt(url.split('?after=')[1] || 0)
        console.log("cursor:", cursor)
        let ret_data = data.slice(cursor, cursor +5)
        return new Promise(resolve => setTimeout(() => resolve({
            "total": 15,
            "data": ret_data,
            "pagination": {
                "cursor": cursor +5
            }
            }), 400)
        )
    }
}

function getUsers (cursor, data = []) {
    return axios.get('/users' + (cursor ? '?after='+cursor : '')) // API supports a cursor param (?after=)
             .then(response => {
               console.log("getting data", response.data)
               if (response.data.length < 1 ) return data
               data.push(...response.data)
               return getUsers(response.pagination.cursor, data)
             })
}
getUsers()
.then(data => console.log("final data", data))
like image 196
Mark Avatar answered Nov 17 '22 11:11

Mark


Have a separate recursive function that takes an array, gets /users, and either pushes to the array and calls itself again, or resolves if there are no more users:

function getUsers () {
  getOne()
    .then((users) => {
      // got all users
    });
}

const getOne = (users = []) => axios.get('/users')
  .then(({ data }) => {
    // Resolve the promise initialized in `getUsers` with the final array:
    if (data.length < 1) return users;
    // Else, push to the array and chain another promise onto the end:
    users.push(...data);
    return getOne(users);
  })
like image 30
CertainPerformance Avatar answered Nov 17 '22 12:11

CertainPerformance