Function that takes an object with optional/default properties as a parameter?

Question

I understand that, using ES6 syntax, a function can be made that takes an object as a parameter and that parameter can have a default value, like so:

function exampleFunction(objParam = {val1: 1, val2: 2}) {
    //...
}

If I call exampleFunction(),objParam is given the default value. However, if I call exampleFunction({val1: 3}), objParam.val2 is undefined. This makes sense, because the default isn't being applied. Is there any way I can make sure that objParam.val2 does have a value, using the ES6 notation? I know I can add checks within the function, but that introduces inconsistency in the code and I'd rather not.

Edit: To clarify, here is a better example:

function exampleFunction(param = 0, objParam = {val1: 1, val2: 2}) {
    return objParam.val1;
}
exampleFunction(); // Returns 1 (this is good)
exampleFunction(1, {val1: 2}); // Returns 2 (this is good)
exampleFunction(1, {val2: 3}); // Returns undefined (I want it to return 1)

And here's what I currently have, which does work but is somewhat inelegant:

function exampleFunction(param = 0, objParam = {val1: 1, val2: 2}) {
    if(objParam.val1 === undefined) objParam.val1 = 1
    if(objParam.val2 === undefined) objParam.val2 = 2
    ...
}

Answer 1

Probably not as clean as you're looking for, but you can do this instead

function exampleFunction(objParams) {
  const defParams = { val1: 1, val2: 2 };

  const finalParams = { ...defParams, ...objParams }
  // final params takes the default params and overwrites any common properties with incoming params

  // ...
}