Awk AND operator

Question

A basic question about AND logical operator. I'm trying to extract some fields in my data file niveles.csv based on values of columns 1 and 2. I'd like to write an awk sentence saying "when field1=date and field2=area then print fields 3 to 5".

My data file looks like

01-08-12;1;0;0;0
01-08-12;2;1;1;1
01-08-12;3;0;0;1
................

awk sentence inside a bash script is

date=01-08-2012
area=8
awk 'BEGIN {FS=";"}  $1 ~ /'$date'/ && $2 ~ /'$area'/ { print $1 " " $2 " "  $3 " " $4 " " $5 }' niveles-rams.cs

But this just gives fields for the three cases where area number has an 8 inside (8,18 and 28) while I just want only area 8 data

01-08-2012 8 0 0 0
01-08-2012 18 2 2 1
01-08-2012 28 2 1 0

Thanks in advance for your attention, sure it is a simple question for experienced users.

Answer 1

Not tested:

awk 'BEGIN {FS=";"}  $1 ~ /'$date'/ && $2 == '$area'{......}'

$2 ~ /8/ -> this means if 2nd field contains 8

$2 == 8 -> this means if 2nd field is equal to 8