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I've tried the below command:
awk '/search-pattern/ {print $1}'
How do I write the else part for the above command?
450
Any awk expression is valid as an awk pattern. The pattern matches if the expression's value is nonzero (if a number) or non-null (if a string). The expression is reevaluated each time the rule is tested against a new input record.
The conditional statement executes based on the value true or false when if-else and if-elseif statements are used to write the conditional statement in the programming. Awk supports all types of conditional statements like other programming languages.
In awk, regular expressions (regex) allow for dynamic and complex pattern definitions. You're not limited to searching for simple strings but also patterns within patterns.
The -f option only controls where the awk program is read from. If enabled, it means that the first filename is in fact the name of a file that contains the awk program. Otherwise, the first filename is the first file to start looking for patterns.
Classic way:
awk '{if ($0 ~ /pattern/) {then_actions} else {else_actions}}' file
$0 represents the whole input record.
Another idiomatic way
based on the ternary operator syntax selector ? if-true-exp : if-false-exp
awk '{print ($0 ~ /pattern/)?text_for_true:text_for_false}'
awk '{x == y ? a[i++] : b[i++]}'
awk '{print ($0 ~ /two/)?NR "yes":NR "No"}' <<<$'one two\nthree four\nfive six\nseven two'
1yes
2No
3No
4yes
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