I have a relatively simple app that plays a sound using AVAudioPlayer
, like this:
NSURL *file3 = [NSURL fileURLWithPath:[NSString stringWithFormat:@"%@/ball_bounce.aiff", [[NSBundle mainBundle] resourcePath]]];
player3 = [[AVAudioPlayer alloc] initWithContentsOfURL:file3 error:nil];
[player3 prepareToPlay];
to later be called to play, like this:
[player3 play];
But this sound is called in multiple places (collisions with a bouncing ball), many times. Sometimes, the ball hits two things in quick enough succession where the sound from the first bounce is still playing when the ball collides a second time. This second bounce then does not produce a sound. How can I make it play a sound every time it collides, even if it involves paying a sound that overlaps an already playing sound?
Any help is greatly appreciated.
One way to solve this problem would to be create a new instance of AVAudioPlayer
if the previous one is already playing:
if([player3 isPlaying]) {
AVAudioPlayer *newPlayer = [[AVAudioPlayer alloc] initWithContentsOfURL:[player3 url]];
[newPlayer setDelegate:self];
[newPlayer play];
}
Then, in the delegate method audioPlayerDidFinishPlaying:successfully:
, you should send the player the -release
message:
- (void)audioPlayerDidFinishPlaying:(AVAudioPlayer *)player successfully:(BOOL)flag {
if(player != player3) {
[player release];
}
}
This is just the way it has to be, as you do need a new source buffer for each concurrent sound playing. :(
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