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This is related to my recent post in Awk code with associative arrays -- array doesn't seem populated, but no error and also to optimizing loop, passing parameters from external file, naming array arguments within awk
My basic problem here is simply to compute from detailed ancient archival financial market data, daily aggregates of #transactions, #shares, value, BY DATE, FIRM-ID, EXCHANGE, etc. Learnt to use associative arrays in awk for this, and was thrilled to be able to process 129+ million lines in clock time of under 11 minutes. Literally before I finished my coffee.
Became a little more ambitious, and moved from 2 array subscripts to 4, and now I am unable to process more than 6500 lines at a time.
Get error messages of the form:
K:\User Folders\KRISHNANM\PAPERS\FII_Transaction_Data>zcat RAW_DATA\2003_1.zip | gawk -f CODE\FII_daily_aggregates_v2.awk > OUTPUT\2003_1.txt&
gawk: CODE\FII_daily_aggregates_v2.awk:33: (FILENAME=- FNR=49300) fatal: more_no des: nextfree: can't allocate memory (Not enough space)
On some runs the machine has told me it lacks as little as 52 KB of memory. I have what I think of a std configuration with Win-7 and 8MB RAM.
(Economist by training, not computer scientist.) I realize that going from 2 to 4 arrays makes the problem computationally much more complex for the computer, but is there something one can do to improve memory management at least a little bit. I have tried closing everything else I am doing. The error always has to do only with memory, never with disk space or anything else.
Sample INPUT:
49290,C198962542782200306,6/30/2003,433581,F5811773991200306,S5405611832200306,B5086397478200306,NESTLE INDIA LTD.,INE239A01016,6/27/2003,1,E9035083824200306,REG_DL_STLD_02,591.13,5655,3342840.15,REG_DL_INSTR_EQ,REG_DL_DLAY_P,DL_RPT_TYPE_N,DL_AMDMNT_DEL_00
49291,C198962542782200306,6/30/2003,433563,F6292896459200306,S6344227311200306,B6110521493200306,GRASIM INDUSTRIES LTD.,INE047A01013,6/27/2003,1,E9035083824200306,REG_DL_STLD_02,495.33,3700,1832721,REG_DL_INSTR_EQ,REG_DL_DLAY_P,DL_RPT_TYPE_N,DL_AMDMNT_DEL_00
49292,C198962542782200306,6/30/2003,433681,F6513202607200306,S1724027402200306,B6372023178200306,HDFC BANK LTD,INE040A01018,6/26/2003,1,E745964372424200306,REG_DL_STLD_02,242,2600,629200,REG_DL_INSTR_EQ,REG_DL_DLAY_D,DL_RPT_TYPE_N,DL_AMDMNT_DEL_00
49293,C7885768925200306,6/30/2003,48128,F4406661052200306,S7376401565200306,B4576522576200306,Maruti Udyog Limited,INE585B01010,6/28/2003,3,E912851176274200306,REG_DL_STLD_04,125,44600,5575000,REG_DL_INSTR_EQ,REG_DL_DLAY_P,DL_RPT_TYPE_N,DL_AMDMNT_DEL_00
49294,C7885768925200306,6/30/2003,48129,F4500260787200306,S1312094035200306,B4576522576200306,Maruti Udyog Limited,INE585B01010,6/28/2003,4,E912851176274200306,REG_DL_STLD_04,125,445600,55700000,REG_DL_INSTR_EQ,REG_DL_DLAY_P,DL_RPT_TYPE_N,DL_AMDMNT_DEL_00
49295,C7885768925200306,6/30/2003,48130,F6425024637200306,S2872499118200306,B4576522576200306,Maruti Udyog Limited,INE585B01010,6/28/2003,3,E912851176274200306,REG_DL_STLD_04,125,48000,6000000,REG_DL_INSTR_EU,REG_DL_DLAY_P,DL_RPT_TYPE_N,DL_AMDMNT_DEL_00
Code
BEGIN { FS = "," }
# For each array subscript variable -- DATE ($10), firm_ISIN ($9), EXCHANGE ($12), and FII_ID ($5), after checking for type = EQ, set up counts for each value, and number of unique values.
( $17~/_EQ\>/ ) { if (date[$10]++ == 0) date_list[d++] = $10;
if (isin[$9]++ == 0) isin_list[i++] = $9;
if (exch[$12]++ == 0) exch_list[e++] = $12;
if (fii[$5]++ == 0) fii_list[f++] = $5;
}
# For cash-in, buy (B), or cash-out, sell (S) count NR = no of records, SH = no of shares, RV = rupee-value.
(( $17~/_EQ\>/ ) && ( $11~/1|2|3|5|9|1[24]/ )) {{ ++BNR[$10,$9,$12,$5]} {BSH[$10,$9,$12,$5] += $15} {BRV[$10,$9,$12,$5] += $16} }
(( $17~/_EQ\>/ ) && ( $11~/4|1[13]/ )) {{ ++SNR[$10,$9,$12,$5]} {SSH[$10,$9,$12,$5] += $15} {SRV[$10,$9,$12,$5] += $16} }
END {
{ print NR, "records processed."}
{ print " " }
{ printf("%-11s\t%-13s\t%-20s\t%-19s\t%-7s\t%-7s\t%-14s\t%-14s\t%-18s\t%-18s\n", \
"DATE", "ISIN", "EXCH", "FII", "BNR", "SNR", "BSH", "SSH", "BRV", "SRV") }
{ for (u = 0; u < d; u++)
{
for (v = 0; v < i; v++)
{
for (w = 0; w < e; w++)
{
for (x = 0; x < f; x++)
#check first below for records with zeroes, don't print them
{ if (BNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]] + SNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]] > 0)
{ BR = BNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
SR = SNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
BS = BSH[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
BV = BRV[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
SS = SSH[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
SV = SRV[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
{ printf("%-11s\t%13s\t%20s\t%19s\t%7d\t%7d\t%14d\t%14d\t%18.2f\t%18.2f\n", \
date_list[u], isin_list[v], exch_list[w], fii_list[x], BR, SR, BS, SS, BV, SV) } }
}
}
}
}
}
}
Expected output
6 records processed.
DATE ISIN EXCH FII BNR SNR BSH SSH BRV SRV
6/27/2003 INE239A01016 E9035083824200306 F5811773991200306 1 0 5655 0 3342840.15 0.00
6/27/2003 INE047A01013 E9035083824200306 F6292896459200306 1 0 3700 0 1832721.00 0.00
6/26/2003 INE040A01018 E745964372424200306 F6513202607200306 1 0 2600 0 629200.00 0.00
6/28/2003 INE585B01010 E912851176274200306 F4406661052200306 1 0 44600 0 5575000.00 0.00
6/28/2003 INE585B01010 E912851176274200306 F4500260787200306 0 1 0 445600 0.00 55700000.00
It is in this case that as the number of input records exceeds 6500, I end up having memory problems. Have about 7 million records in all.
For a 2 array subscript problem, albeit on a different data set, where 129+ million lines were processed in clock time of 11 minutes using the same GNU-AWK on the same machine, see optimizing loop, passing parameters from external file, naming array arguments within awk
Question: is it the case that awk is not very smart with memory management, but that some other more modern tools (say, SQL) would accomplish this task with the same memory resources? Or is this simply a characteristic of associative arrays, which I found magical in enabling me to avoid many passes over the data, many loops and SORT procedures, but which maybe work well up to 2 array subscripts, and then face exponential memory resource costs after that?
Afterword: the super-detailed almost-idiot-proof tutorial along with the code provided by Ed Morton in comments below makes a dramatic difference, especially his GAWK script tst.awk. He taught me about (a) using SUBSEP intelligently (b) tackling needless looping, which is crucial in this problem which tends to have very sparse arrays, with various AWK constructs. Compared to performance with my old code (only up to 6500 lines of input accepted on one machine, another couldn't even get that far), the performance of Ed Morton's tst.awk can be seen from the table below:
**filename start end min in ln out lines
2008_1 12:08:40 AM 12:27:18 AM 0:18 391438 301160
2008_2 12:27:18 AM 12:52:04 AM 0:24 402016 314177
2009_1 12:52:05 AM 1:05:15 AM 0:13 302081 238204
2009_2 1:05:15 AM 1:22:15 AM 0:17 360072 276768
2010_1 "slept" 507496 397533
2010_2 3:10:26 AM 3:10:50 AM 0:00 76200 58228
2010_3 3:10:50 AM 3:11:18 AM 0:00 80988 61725
2010_4 3:11:18 AM 3:11:47 AM 0:00 86923 65885
2010_5 3:11:47 AM 3:12:15 AM 0:00 80670 63059**
Times were obtained simply from using %time% on lines before and after tst.awk was executed, all put in a simple batch script, "min" is the clock time taken (per whatever rounding EXCEL does by default), "in ln" and "out lines" are lines of input and output, respectively. From processing the entire data that we have, from Jan 2003 to Jan 2014, we find the theoretical max number of output records = #dates*#ISINs*#Exchanges*#FIIs = 2992*2955*567*82268, while the actual number of total output lines is only 5,261,942, which is only 1.275*10^(-8) of the theoretical max -- very sparse indeed. That there was sparseness, we did guess earlier, but that the arrays could be SO sparse -- which matters a lot for memory management -- we had no way of telling till something actually completed, for a real data set. Time taken seems to increase exponentially in input size, but within limits that pose no practical difficulty. Thanks a ton, Ed.
594
There is no problem with associative arrays in general. In awk (except gawk for true 2D arrays) an associative array with 4 subscripts is identical to one with 2 subscripts since in reality it only has one subscript which is the concatenation of each of the pseudo-subscripts separated by SUBSEP.
Given you say I am unable to process more than 6500 lines at a time. the problem is far more likely to be in the way you wrote your code than any fundamental awk issue so if you'd like more help, post a small script with sample input and expected output that demonstrates your problem and attempted solution to see if we have suggestions on way to improve it's memory usage.
Given your posted script, I expect the problem is with those nested loops in your END section When you do:
for (i=1; i<=maxI; i++) {
for (j=1; j<=maxJ; j++) {
if ( arr[i,j] != 0 ) {
print arr[i,j]
}
}
}
you are CREATING arr[i,j] for every possible combination of i and j that didn't exist prior to the loop just by testing for arr[i,j] != 0. If you instead wrote:
for (i=1; i<=maxI; i++) {
for (j=1; j<=maxJ; j++) {
if ( (i,j) in arr ) {
print arr[i,j]
}
}
}
then the loop itself would not create new entries in arr[].
So change this block:
if (BNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]] + SNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]] > 0)
{
BR = BNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
SR = SNR[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
BS = BSH[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
BV = BRV[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
SS = SSH[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
SV = SRV[date_list[u],isin_list[v],exch_list[w],fii_list[x]]
which is probably unnecessarily turning each of BNR, SNR, BSH, BRV, SSH, and SRV into huge but highly sparse arrays, to something like this:
idx = date_list[u] SUBSEP isin_list[v] SUBSEP exch_list[w] SUBSEP fii_list[x]
BR = (idx in BNR ? BNR[idx] : 0)
SR = (idx in SNR ? SNR[idx] : 0)
if ( (BR + SR) > 0 )
{
BS = (idx in BSH ? BSH[idx] : 0)
BV = (idx in BRV ? BRV[idx] : 0)
SS = (idx in SSH ? SSH[idx] : 0)
SV = (idx in SRV ? SRV[idx] : 0)
and let us know if that helps. Also check your code for other places where you might be doing the same.
The reason you have this problem with 4 subscripts when you didn't with 2 is simply that you have 4 levels of nesting in the loops now creating much larger and more sparse arrays when when you just had 2.
Finally - you have some weird syntax in your script, some of which @MarkSetchell pointed out in a comment, and your script isn't as efficient as it could be since you're not using else statements and so testing for multiple conditions that can't possibly all be true and you're testing the same condition repeatedly, and it's not robust as you aren't anchoring your REs (e.g you test /4|1[13]/ instead of /^(4|1[13])$/ so for example your 4 would match on 14 or 41 etc. instead of just 4 on its own) so change your whole script to this:
$ cat tst.awk
BEGIN { FS = "," }
# For each array subscript variable -- DATE ($10), firm_ISIN ($9), EXCHANGE ($12), and FII_ID ($5), after checking for type = EQ, set up counts for each value, and number of unique values.
$17 ~ /_EQ\>/ {
if (!seenDate[$10]++) date_list[++d] = $10
if (!seenIsin[$9]++) isin_list[++i] = $9
if (!seenExch[$12]++) exch_list[++e] = $12
if (!seenFii[$5]++) fii_list[++f] = $5
# For cash-in, buy (B), or cash-out, sell (S) count NR = no of records, SH = no of shares, RV = rupee-value.
idx = $10 SUBSEP $9 SUBSEP $12 SUBSEP $5
if ( $11 ~ /^([12359]|1[24])$/ ) {
++BNR[idx]; BSH[idx] += $15; BRV[idx] += $16
}
else if ( $11 ~ /^(4|1[13])$/ ) {
++SNR[idx]; SSH[idx] += $15; SRV[idx] += $16
}
}
END {
print NR, "records processed."
print " "
printf "%-11s\t%-13s\t%-20s\t%-19s\t%-7s\t%-7s\t%-14s\t%-14s\t%-18s\t%-18s\n",
"DATE", "ISIN", "EXCH", "FII", "BNR", "SNR", "BSH", "SSH", "BRV", "SRV"
for (u = 1; u <= d; u++)
{
for (v = 1; v <= i; v++)
{
for (w = 1; w <= e; w++)
{
for (x = 1; x <= f; x++)
{
#check first below for records with zeroes, don't print them
idx = date_list[u] SUBSEP isin_list[v] SUBSEP exch_list[w] SUBSEP fii_list[x]
BR = (idx in BNR ? BNR[idx] : 0)
SR = (idx in SNR ? SNR[idx] : 0)
if ( (BR + SR) > 0 )
{
BS = (idx in BSH ? BSH[idx] : 0)
BV = (idx in BRV ? BRV[idx] : 0)
SS = (idx in SSH ? SSH[idx] : 0)
SV = (idx in SRV ? SRV[idx] : 0)
printf "%-11s\t%13s\t%20s\t%19s\t%7d\t%7d\t%14d\t%14d\t%18.2f\t%18.2f\n",
date_list[u], isin_list[v], exch_list[w], fii_list[x], BR, SR, BS, SS, BV, SV
}
}
}
}
}
}
I added seen in front of 4 array names just because by convention arrays testing for the pre-existence of a value are typically named seen. Also, when populating the SNR[] etc arrays I created an idx variable first instead of repeatedly using the field numbers every time for both ease of changing it in future and mostly because string concatenation is relatively slow in awk and that's whats happening when you use multiple indices in an array so best to just do the string concatenation once explicitly. And I changed your date_list[] etc arrays to start at 1 instead of zero because all awk-generated arrays, strings and field numbers start at 1. You CAN create an array manually that starts at 0 or -357 or whatever number you want but it'll save shooting yourself in the foot some day if you always start them at 1.
I expect it could be made more efficient still by restricting the nested loops to only values that could exist for the enclosing loop index combinations (e.g. not every value of u+v+w is possible so there will be times when you shouldn't bother looping on x). For example:
$ cat tst.awk
BEGIN { FS = "," }
# For each array subscript variable -- DATE ($10), firm_ISIN ($9), EXCHANGE ($12), and FII_ID ($5), after checking for type = EQ, set up counts for each value, and number of unique values.
$17 ~ /_EQ\>/ {
if (!seenDate[$10]++) date_list[++d] = $10
if (!seenIsin[$9]++) isin_list[++i] = $9
if (!seenExch[$12]++) exch_list[++e] = $12
if (!seenFii[$5]++) fii_list[++f] = $5
# For cash-in, buy (B), or cash-out, sell (S) count NR = no of records, SH = no of shares, RV = rupee-value.
idx = $10 SUBSEP $9 SUBSEP $12 SUBSEP $5
if ( $11 ~ /^([12359]|1[24])$/ ) {
seen[$10,$9]
seen[$10,$9,$12]
++BNR[idx]; BSH[idx] += $15; BRV[idx] += $16
}
else if ( $11 ~ /^(4|1[13])$/ ) {
seen[$10,$9]
seen[$10,$9,$12]
++SNR[idx]; SSH[idx] += $15; SRV[idx] += $16
}
}
END {
printf "d = %d\n", d | "cat>&2"
printf "i = %d\n", i | "cat>&2"
printf "e = %d\n", e | "cat>&2"
printf "f = %d\n", f | "cat>&2"
print NR, "records processed."
print " "
printf "%-11s\t%-13s\t%-20s\t%-19s\t%-7s\t%-7s\t%-14s\t%-14s\t%-18s\t%-18s\n",
"DATE", "ISIN", "EXCH", "FII", "BNR", "SNR", "BSH", "SSH", "BRV", "SRV"
for (u = 1; u <= d; u++)
{
date = date_list[u]
for (v = 1; v <= i; v++)
{
isin = isin_list[v]
if ( (date,isin) in seen )
{
for (w = 1; w <= e; w++)
{
exch = exch_list[w]
if ( (date,isin,exch) in seen )
{
for (x = 1; x <= f; x++)
{
fii = fii_list[x]
#check first below for records with zeroes, don't print them
idx = date SUBSEP isin SUBSEP exch SUBSEP fii
if ( (idx in BNR) || (idx in SNR) )
{
if (idx in BNR)
{
bnr = BNR[idx]
bsh = BSH[idx]
brv = BRV[idx]
}
else
{
bnr = bsh = brv = 0
}
if (idx in SNR)
{
snr = SNR[idx]
ssh = SSH[idx]
srv = SRV[idx]
}
else
{
snr = ssh = srv = 0
}
printf "%-11s\t%13s\t%20s\t%19s\t%7d\t%7d\t%14d\t%14d\t%18.2f\t%18.2f\n",
date, isin, exch, fii, bnr, snr, bsh, ssh, brv, srv
}
}
}
}
}
}
}
}
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