I've written a script that uses associative arrays in bash (v 4).
It works fine on my local machine which is using 4.1.5(1)-release.
On the production machine, using 4.1.0(1)-release the following line, which declares the assoc array, fails:
declare -A uniqjars
with the message:
/script.sh: line 11: declare: -A: invalid option
declare: usage: declare [-afFirtx] [-p] [name[=value] ...]
I was under the impression this was a general bash 4 feature?
In the man for bash on the production machine it discusses using -A so I assume it should work.
Associative arrays are created using
declare -A name.
I can confirm the script is using the right version of bash by printing out the value of echo 'bash -version.
What could I be doing wrong?
Make sure the version of bash being invoked as interpreter at the top of your shell script (#!/bin/bash or whatever) is also version 4. If you're doing:
bash --version
and it's giving you v4, do a which bash to check it's location.
The following seems to be a typical scenario on macOS after installing a newer Bash with Homebrew:
/bin/bash is the old Bash, 3.2/usr/local/bin/bash is the new Bash that knows about associative arrays (4.0 or newer)type bash points to /usr/local/bin/bash and bash --version is the new one (because it resolves to /usr/local/bin/bash --version)However, scripts with a #!/bin/bash shebang line that are run with ./script will use the old Bash (the scenario in the question). Solutions are:
bash script: the new Bash will be used. Disadvantage: you always have to call it like that.#!/usr/local/bin/bash. Disadvantage: on many systems, there is no Bash in /usr/local/bin and your script isn't portable any longer.#!/usr/bin/env bash. This will use the first bash in your PATH, which should be the new one. This is pretty portable; the only downside is that you don't know exactly which Bash will be executed.See also these Q&A:
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