assigning char pointer to char and char array variable

Question

Why is the following ok?

    char *a;
    char b[]="asdf";
    a=b;

But the following is not?

    char a[10];
    char b[]="asdf";
    a=b;

The above gives error: incompatible types in assignment.

Answer 1

Both are not ok.

Maybe you were attempting ,

char *a;
char b[]="asdf";
a=b;