I know that when calling a function in assembly r0 contains the first argument up to r3 being the fourth. I know that when it goes beyond four the stack pointer is used but I'm not too sure on the specifics. Does r0-r3 still hold the first four and the rest goes on the stack? I'm looking at the following piece of assembly trying to understand what it's doing to call mach_msg (a function with seven arguments). On entry to this code, r0 and r1 contain the two arguments
var_38 = -0x38
var_34 = -0x34
var_30 = -0x30
var_2C = -0x2C
var_24 = -0x24
var_20 = -0x20
var_18 = -0x18
var_14 = -0x14
var_10 = -0x10
var_C = -0xC
00001220
00001220 PUSH {R7,LR}
00001222 MOV R7, SP
00001224 SUB SP, SP, #0x30
00001226 MOV R2, (_NDR_record_ptr - 0x1232) ; _NDR_record_ptr
0000122E ADD R2, PC ; _NDR_record_ptr
00001230 LDR R2, [R2] ; _NDR_record
00001232 LDR R3, [R2]
00001234 LDR R2, [R2,#4]
00001236 STR R2, [SP,#0x38+var_10]
00001238 MOVS R2, #0x24 ; '$'
0000123A STR R3, [SP,#0x38+var_14]
0000123C MOVS R3, #0
0000123E STRB.W R1, [SP,#0x38+var_C]
00001242 MOVS R1, #0x13
00001244 STR R1, [SP,#0x38+var_2C]
00001246 MOVS R1, #1
00001248 STR R0, [SP,#0x38+var_24]
0000124A MOV R0, 0x1E84EA
00001252 STR R3, [SP,#0x38+var_20]
00001254 STR R3, [SP,#0x38+var_38]
00001256 STR R3, [SP,#0x38+var_34]
00001258 STR R0, [SP,#0x38+var_18]
0000125A STR R3, [SP,#0x38+var_30]
0000125C ADD R0, SP, #0x38+var_2C
0000125E BLX _mach_msg
00001262 ADD SP, SP, #0x30
00001264 POP {R7,PC}
Here are the definitions for the stuff being called and used:
typedef struct {
unsigned char mig_vers;
unsigned char if_vers;
unsigned char reserved1;
unsigned char mig_encoding;
unsigned char int_rep;
unsigned char char_rep;
unsigned char float_rep;
unsigned char reserved2;
} NDR_record_t;
extern NDR_record_t NDR_record;
extern mach_msg_return_t mach_msg(
mach_msg_header_t *msg,
mach_msg_option_t option,
mach_msg_size_t send_size,
mach_msg_size_t rcv_size,
mach_port_name_t rcv_name,
mach_msg_timeout_t timeout,
mach_port_name_t notify);
From what I understand, the stack pointer is being reversed 48 bytes for variables. Is that 48 bytes for the extra 3 arguments or for all of them?
Except for functions with variable-length argument lists, the number of arguments in a function call must be the same as the number of parameters in the function definition. This number can be zero. The maximum number of arguments (and corresponding parameters) is 253 for a single function.
ARM uses the branch and link instruction (BL) to call a function and moves the link register to the PC (MOV PC, LR) to return from a function. Code Example 6.20 shows the main function calling the simple function. main is the caller, and simple is the callee.
Many times, we tend to add too many parameters to a function. But that's not the best idea: on the contrary, when a function requires too many arguments, grouping them into coherent objects helps writing simpler code.
To call an external function, such as NetRun's "print_int", or a standard C library function like "exit", you need to tell the assembler the function is "extern". "extern" isn't actually an instruction--it doesn't show up in the disassembly--it's just a message to the assembler, often called a pseudoinstruction.
Of the 48 bytes, 12 are for the extra 3 parameters, and the others are for local variables. You can see this in the code where the function passes four parameters in r0 through r3, another in [SP,#0x38+var_38] (which if you do the math resolves to just [sp]), another in [sp,#4], and the last in [sp,#8].
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