Menu
If there are no compile time binding in java, do this mean all binding are done at runtime?
But as per OOPs concept for runtime binding, functions must have virtual keyword..ARE all methods implicitly virtual in java or is there any compile time binding exist in java
If there is any compile time binding, can you give me some specific situation, or links to further information
436
In Java, methods are virtual by default and can be made non-virtual by using the final keyword. For example, in the following java program, show() is by default virtual and the program prints “Derived::show() called“.
Abstract: In Java all methods are virtual, meaning that the most derived method is always called. In earlier versions of Java, it was possible to trick the JVM by replacing the superclass with another wheere the method is defined as "private".
Java interface methods are all virtual. They must be virtual because they rely on the implementing classes to provide the method implementations. The code to execute will only be selected at run time. Example with virtual functions with abstract classes.
Q) which of the following is true about methods in an interface in java? An interface can contain only abstract method.
All non-static, non-final and non-private methods are virtual by default in Java. However JVM is clever enough to find classes having only one implementation of given method and turn it into static binding.
This way you don't have to remember about virtual keyword (ever experienced memory leak due to missing virtual on destructor in C++?) while the performance is not impacted that much.
98
Non-static method invocation is the main (only) dynamic aspect of Java. All methods are virtual in Java. This does not apply to static methods, which are bound at compile time, based on the static type of object.
29
If you love us? You can donate to us via Paypal or buy me a coffee so we can maintain and grow! Thank you!
Donate Us With
