So, the interrupts seem to work insofar as "interrupting" when an event happens. My only problem is that I the interrupts will occur 2-3 times and everything essentially stops (Serial out, everything).
I was programming the board to output serially a calculated distance based on the output of the HC-SR04 distance IC. The distances are calculated accurately but, like I said earlier, everything seems to freeze. Below is both the code and an image of the serial monitor.
#define TRIGPIN 4
#define ECHOPIN 3
#define RED 2
#define GREEN 13
#define INTNUM 1 //interrupt pin 1 is digital pin 3 on the duemilanove
#define PULSE 10 //microseconds
#define CYCLETIME 50 //milliseconds
void ledWrite(int), trigPulse(), getTime();
int millisNow, millisPrev = 0;
int microsPrev;
boolean isHigh = false;
void setup() {
Serial.begin (9600);
pinMode(TRIGPIN, OUTPUT);
pinMode(ECHOPIN, INPUT);
pinMode(RED, OUTPUT);
pinMode(GREEN, OUTPUT);
attachInterrupt(INTNUM, getTime, CHANGE);
}
void loop() {
trigPulse();
// some other code while waiting on HC-SR04 to interrupt us when echo goes HIGH
}
void trigPulse(){
if( (millisNow = millis()) - millisPrev >= CYCLETIME){ //sufficient cycle time
digitalWrite(TRIGPIN, HIGH);
delayMicroseconds(PULSE);
digitalWrite(TRIGPIN, LOW);
millisPrev = millisNow; //reset clock
}
return;
}
void ledWrite(int dTime){
int distance = dTime/58.2;
if (distance < 4) {
digitalWrite(RED,HIGH);
digitalWrite(GREEN,LOW);
}
else {
digitalWrite(RED,LOW);
digitalWrite(GREEN,HIGH);
}
if (distance >= 200 || distance <= 0){
Serial.println("Out of range");
}
else {
Serial.print(distance);
Serial.println(" cm");
}
}
void getTime(){
int timeNow = micros();
Serial.println("Interrupted");
if(isHigh == false){
microsPrev = timeNow; //get time now, pin LOW->HIGH
isHigh = true;
Serial.println("Returning ..");
return;
}
else { //pin HIGH->lOW
ledWrite(timeNow - microsPrev);
isHigh = false;
microsPrev = micros();
Serial.println("Returning ..");
return;
}
return;
}
You can use Serial. print() inside an interrupt for debugging, for example if you're not sure when the interrupt is triggered. But it also has its own source of problems. The best way to print something from an interrupt, is simply to set a flag inside the interrupt, and poll this flag inside the main loop() program.
The serial data is captured using an interrupt to put each character into the serial input buffer. If you add any additional processing to that interrupt or trigger another interrupt then you may lose incoming characters because the arduino disables interrupts when it is in an interrupt handler.
ArduinoTom: What happens if both external interrupts are triggered at the same time? The interrupt with the higher priority runs first.
When the event or interrupt happens, the processor takes immediate notice, saves its execution state, runs a small chunk of code (often called the interrupt handler or interrupt service routine), and then returns back to whatever it was doing before. Let's try one simple interrupt using Arduino UNO.
I know this is an old thread, but I just came by it having my own problems. The problem here is that you cannot use:
Serial.Print()
Within an interrupt service routine. The reason that the Serial.Print()
doesn't work within an ISR is that it uses interrupts to pull the characters out of the serial buffer, but interrupts of a certain level are masked within the ISR. What basically happens is that the arduino throws out all other interrupts that are of a lower priority, which Serial.Read() falls into.
It is documented in a number of places: link1, link2, link3
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