append multiple dictionaries into one dictionary sequentially in python

Question

I have several dictionaries like this

dict1 = {0: 33.422, 1: 39.2308, 2: 30.132}
dict2 = {0: 42.2422, 1: 43.342, 2: 42.424}
dict3 = {0: 13.422, 1: 9.2308, 2: 20.132}

I am aware that I could combine them together into one dictionary using the code

dicts = dict1, dict2, dict3

And it returns the result like this

({0: 33.422, 1: 39.2308, 2: 30.132}, {0: 42.2422, 1: 43.342, 2: 42.424}, {0: 13.422, 1: 9.2308, 2: 20.132})

However, what if the dictionaries come sequentially? How can I get the same results? I tried the following code

dicts = {}
dicts = dicts, dict1
dicts = dicts, dict2
dicts = dicts, dict3

But it returns the result like this

((({}, {0: 33.422, 1: 39.2308, 2: 30.132}), {0: 42.2422, 1: 43.342, 2: 42.424}), {0: 13.422, 1: 9.2308, 2: 20.132})

How can we remove the first stuff? I'm using python 3 on windows 7. And all the dictionaries are in a "MyDataFileReader" type under avro package.

Answer 1

If I understand correctly you want a list of dictionaries:

dict1 = {0: 33.422, 1: 39.2308, 2: 30.132}
dict2 = {0: 42.2422, 1: 43.342, 2: 42.424}
dict3 = {0: 13.422, 1: 9.2308, 2: 20.132}
dicts = []
dicts.append(dict1)
dicts.append(dict2)
dicts.append(dict3)

Answer 2

As @MMF already stated in his comment: a, b, c creates a tuple containing a, b and c (in that order).

What you want to do, is "updating" the dictionary:

dict = {}
dict.update(dict1)
dict.update(dict2)
dict.update(dict3)

Or, if you don't want that dict3 or dict2 overwrite stuff:

dict = {}
dict.update(dict3)
dict.update(dict2)
dict.update(dict1)

Or

def update_without_overwriting(d, x):
    dict.update({k: v for k, v in x.items() if k not in d})

dict = {}
update_without_overwriting(dict, dict1)
update_without_overwriting(dict, dict2)
update_without_overwriting(dict, dict3)

If you just want a tuple containing all dicts however, use this:

dict = dict1, dict2
dict += dict3,