Why doesn't `finally: return` propagate an unhandled exception? [duplicate]

Question

Why does the function not raise the exception? It's apparently not caught.

def f():
    try:
        raise Exception
    finally:
        return "ok"

print(f())  # ok

Answer 1

This is explicitly explained in the documentation:

If an exception occurs in any of the clauses and is not handled, the exception is temporarily saved. The finally clause is executed. [..] If the finally clause executes a return or break statement, the saved exception is discarded

Answer 2

From the docs:

A finally clause is always executed before leaving the try statement.

^{@deceze quoted the more relevant part in his answer}

The function returns the string in the finally clause and doesn't raise the exception since it returned, and that what gets printed.

If you try to execute:

>>> try:
...     raise Exception
... finally:
...     print('yes')
... 
yes
Traceback (most recent call last):
  File "<stdin>", line 2, in <module>
Exception

Then as you can see, "yes" is printed and the exception is thrown after the print statement.