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Apache Camel conditional routing

I have a service which has two operations.

RegisterUser
UpdateUser

I have a camel rout:

<camel:route id="myRoute">
    <camel:from uri="cxf:bean:myListenerEndpoint?dataFormat=POJO&amp;synchronous=true" />            
    <camel:bean ref="processor" method="processMessage"/>
    <camel:to uri="xslt:file:resources/service/2.0.0/UserRegistration.xsl"/>
    <camel:to uri="cxf:bean:myTargetEndpoint"/>
</camel:route>

In my processor bean, when I specify:

RegisterUser registerUser = exchange.getIn().getBody(RegisterUser.class);

I get the register user object. Everything works fine. The problem is that I want camel to route my request conditionally, for e.g:

If the service operation is RegisterUser I want to route the message to my specific bean and if the service operation is UpdateUser I want to route the message to the other bean.

I have tried to use camel xPath, but it not seems to be working.

<camel:route id="myRoute">
    <camel:from uri="cxf:bean:myListenerEndpoint?dataFormat=POJO&amp;synchronous=true" />  
    <camel:choice>
        <camel:when>
            <camel:xpath>
                //RegisterUser
            </camel:xpath>
            <camel:bean ref="processor" method="processMessage"/>
            <camel:to uri="xslt:file:resources/service/2.0.0/UserRegistration.xsl"/>
        </camel:when>
    </camel:choice>                        
    <camel:to uri="cxf:bean:myTargetEndpoint"/>
</camel:route>

I was searching how to set up camel to route to the different targets but did not find anything. Maybe somebody knows where might be the problem?

like image 870
Paulius Matulionis Avatar asked Jul 27 '12 15:07

Paulius Matulionis


2 Answers

The information of the operation required will be in the header of the message.

The header you are looking for is called 'operationName'

So here is an example :

<camelContext xmlns="http://camel.apache.org/schema/blueprint">
    <route id="example">
        <from uri="cxf:bean:myListenerEndpoint?dataFormat=POJO&amp;synchronous=true" />
        <log message="The expected operation is :: ${headers.operationName}" />
        <choice>
            <when>
                <simple>${headers.operationName} == 'RegisterUser'</simple>
                    <bean ref="processor" method="processMessage"/>
                <to uri="xslt:file:resources/service/2.0.0/UserRegistration.xsl"/>
            </when>
            <when>
                <simple>${headers.operationName} == 'UpdateUser'</simple>
                <!-- Do the update user logic here -->
                <bean ref="processor" method="updateUser" />
            </when>
        </choice>
    <to uri="cxf:bean:myTargetEndpoint"/>
    </route>
</camelContext> 

(Note the example is using apache aries blueprint - but it will be identical for spring, other than the namespace)

like image 127
AlanFoster Avatar answered Sep 28 '22 07:09

AlanFoster


try using camel-simple expressions instead of xpath for this...

<when><simple>${body} is 'com.RegisterUser'</simple><to uri="..."/></when>
like image 21
Ben ODay Avatar answered Sep 28 '22 06:09

Ben ODay