I have an app where i want to lazy load two modules in the same moment with the same route path.
My routing module would look like this :
{
path: 'mypath',
loadChildren: () => HomeModule,
canLoad: [HomeGuard]
},
{
path: 'mypath',
loadChildren: () => AdvisorModule,
canLoad: [AdvisorGuard]
},
but this lead to load only the first one
i cant' find anyway to do it like this for example :
{
path: 'mypath',
loadChildren: () => HomeModule, advisor module // ??
canLoad: [// ??]
},
I don't want also to import one of them in the other , as like this , only one module would be lazy loaded and the other automatically
How may it do it ??
You could rework things like this:
const routes: Routes = [
{
path: 'mypath/home',
loadChildren: () => HomeModule,
canLoad: [HomeGuard]
},
{
path: 'mypath/advisor',
loadChildren: () => AdvisorModule,
canLoad: [AdvisorGuard]
},
]
In other words move the route path to your module outside to the parent module, in this case I assume those are 'adviser' and 'home'
And then just start in the module routing with a redirect solution and/or a path like so:
Home module routing:
const routes: Routes = [
{
path: '', // <-- in your current solution probably 'home'
component: HomeParentComponent,
children: [
{ path: '', redirectTo: 'childOne', pathMatch: 'full' },
{ path: 'childOne', component: HomeChildComponentOne },
],
},
];
Advisor module routing:
const routes: Routes = [
{
path: '', // <-- in your current solution probably 'advisor'
component: AdvisorParentComponent,
children: [
{ path: '', redirectTo: 'childOne', pathMatch: 'full' },
{ path: 'childOne', component: AdvisorChildComponentOne },
],
},
];
This works nicely, you should be able to navigate to:
'/mypath/home'
and end up inside your HomeParentComponent
with router outlet of HomeChildComponent
one.
'/mypath/advisor'
and end up inside your AdvisorParentComponent
with router outlet of AdvisorChildComponent
one.
In case you don't want a child component inside your router outlet it is even simpler, you can just remove the child routes and redirect.
Note: If this solution doesn't resolve your issue, then please share more details on your module routing so I can get a better picture of your desired route configuration.
You need to re-arrange your routes by one level and you also need to add auxiliary routes for the extra components you want to load.
This works with Angular 9 (probably with 8 too)
{
path: 'home',
component: HostingComponentWithOutlets,
children: [
{
path: 'featureOne',
loadChildren: () => import('xxxxx').then(m => m.FeatureOneModule),
canLoad: [featureOneGuard]
},
{
path: 'featureTwo',
outlet: 'outletAux1',
loadChildren: () => import('yyyyy').then(m => m.FeatureTwoModule),
canLoad: [featureTwoGuard]
},
// you can even load more components to different outlets from the same module
// and update redirectTo and routerLink accordingly
//{
// path: 'featureThree',
// outlet: 'outletAux2',
// loadChildren: () => import('yyyyy').then(m => m.featureTwoModule),
// canLoad: [featureTwoGuard]
//},
{
path: '',
redirectTo:
'/absolute/path/to/home(featureOne/path-to-featureOne-component//outletAux1:featureTwo/path-to-featureTwo-component)',
pathMatch: 'full'
}
]
},
{ path: '', redirectTo: 'home', pathMatch: 'full' }
Hitting the 'home' route will lazy load all required modules.
In your HostingComponentWithOutlets
html template where you need to link to 'featureOne':
<a [routerLink]="featureOne/path-to-featureOne-component"
and if you want to go straight to the full route with the auxiliary routes from a template:
<a [routerLink]="['.', { outlets: { 'primary': ['featureOne', 'path-to-featureOne-component'], 'outletAux1': ['featureTwo', 'path-to-featureTwo-component'] } }]"
FeatureOneModule
should define 'path-to-featureOne-component' and FeatureTwoModule
should define 'path-to-featureTwo-component' in their equivalent route definitions.
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