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android:shape="line" not visible

I have the following drawable shape:

<?xml version="1.0" encoding="utf-8"?>
<shape xmlns:android="http://schemas.android.com/apk/res/android"
   android:shape="line" >

   <stroke
      android:width="1dp"
      android:color="#e0e0e0" />

</shape>

And use this with this image:

  <ImageView
     android:layout_width="match_parent"
     android:layout_height="1dp"
     android:layout_marginTop="8dp"
     android:src="@drawable/line" />

When I set android:layout_height to 1dp, the shape is not visible. If the android:layout_height is set to 2dp, the shape is visible.

Why do I have to use a height of 2dp?

Ralph

like image 512
Ralph Bergmann Avatar asked Oct 03 '22 00:10

Ralph Bergmann


1 Answers

It's a stroke, so it goes around the shape. Meaning it passes the line on both sides, so it will need twice the width of the stroke.

You could just set <size> tag in your shape and put that on 1dp and <solid android:color=""> for the color

like image 163
dumazy Avatar answered Oct 08 '22 01:10

dumazy