Android using Gradle Build flavors in the code like an if case

Question

I'm trying to work with build flavors. In my build.gradle I've defined 2 flavors, a normal flavor and an admin flavor.

Basicly, the admin flavor has an extra button on the main activity.

I understand that I can define different packages/classes for different flavors. But is there a way to make a sort of if case to add/remove a piece of code depending on the flavor?

Basicly, I would need two versions of an Activity. But I don't want two entire different versions of the activity and maintain them.

So in my activity I would like to do

=> gradle check if flavor is 'admin'

=> if yes, add this code of the button

Is this possible? Or would you need two different physical activities and thus maintain both of them when you add functionality afterwards.

Answer 1

BuildConfig.FLAVOR gives you combined product flavor. So if you have only one flavor dimension:

productFlavors {     normal {     }      admin {     } } 

Then you can just check it:

if (BuildConfig.FLAVOR.equals("admin")) {     ... } 

But if you have multiple flavor dimensions:

flavorDimensions "access", "color"  productFlavors {     normal {         dimension "access"     }      admin {         dimension "access"     }      red {         dimension "color"     }      blue {         dimension "color"     } } 

there are also BuildConfig.FLAVOR_access and BuildConfig.FLAVOR_color fields so you should check it like this:

if (BuildConfig.FLAVOR_access.equals("admin")) {     ... } 

And BuildConfig.FLAVOR contains full flavor name. For example, adminBlue.

Answer 2

To avoid plain string in the condition, you can define a boolean property:

productFlavors {     normal {         flavorDimension "access"         buildConfigField 'boolean', 'IS_ADMIN', 'false'     }      admin {         flavorDimension "access"         buildConfigField 'boolean', 'IS_ADMIN', 'true'     } } 

Then you can use it like this:

if (BuildConfig.IS_ADMIN) {     ... }